Chapter 10: Problem 1
Plot the dissociation fraction \(\alpha\) of \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{NH}_{4} \mathrm{OH}\) as a function of PH. Use pK \(=4.6\) for \(\mathrm{CH}_{3} \mathrm{COOH}\) and \(\mathrm{pK}=9.3\) for \(\mathrm{NH}_{4} \mathrm{OH}\).
Short Answer
Expert verified
For \( \mathrm{CH}_{3} \mathrm{COOH} \): \( \alpha = \frac{1}{1 + 10^{(4.6 - \text{pH})}} \). For \( \mathrm{NH}_{4} \mathrm{OH} \): \( \alpha = \frac{1}{1 + 10^{(\text{pH} - 9.3)}} \). Plot these functions over a pH range of 0 to 14.
Step by step solution
Key Concepts
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