Find the escape speed on Titan. What is the limiting molecular weight of gases that could be retained by Titan's gravity? (Hint: Use the ideas presented in Box 7-2 and assume an average atmospheric temperature of \(95 \mathrm{~K}\).)

Short Answer

Expert verified
The escape speed on Titan is approximately \(2.63 \, km/s\) or \(2630 \, m/s\). The limiting molecular weight of gasses that could be retained by Titan's gravity is approximately \(28.3 \, u\).

Step by step solution

01

Calculate the escape speed

The formula of escape speed is given by \(v_{e}=\sqrt{2gr}\) where \(g\) is the gravitational acceleration and \(r\) is the radius of the planet. For Titan, \(g = 1.352 \, m/s^{2}\) and \(r = 2575 \, km\). Substituting these values in the given formula, the escape speed, \(v_{e}\), is calculated.
02

Convert escape speed to SI units

The escape speed is calculated in units of km/s, but the calculation requires units of m/s, thus the escape speed must be converted from km/s to m/s by multiplying by 1000.
03

Calculate the limiting molecular weight

The limiting molecular weight (\(M\)) can be found by using the formula \(M = \frac {2kT}{v_{e}^{2}}\), where \(k\) is Boltzmann's constant (\(1.38064852 x 10^{-23} \, m^{2}kg/s^{2}K\)), \(T\) is the average atmospheric temperature (given as \(95 \, K\)), and \(v_{e}\) is the escape speed calculated in step 2. Substitute these values into the formula to calculate the limiting molecular weight.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Acceleration
Gravitational acceleration is a measure of the force of gravity at a specific location. On Earth, this value is approximately 9.8 m/s², but this can vary on other celestial bodies like Titan, one of Saturn's moons. Understanding gravitational acceleration is crucial when figuring out the escape speed from a planet or moon because it determines how much speed an object needs to break free from its gravitational pull.

For Titan, the gravitational acceleration is considerably smaller at 1.352 m/s². This lower value is due to Titan's smaller mass relative to Earth. To find the escape velocity, one must use the formula: \(v_{e} = \sqrt{2gr}\), where \(g\) represents the gravitational acceleration and \(r\) the radius of Titan. This formula illustrates that the required escape speed is dependent on both the value of \(g\) and the radius of the moon. The lower gravitational acceleration on Titan means that objects require less speed to escape its gravity compared to Earth, facilitating exploration and potential future missions.
Atmospheric Temperature
The atmospheric temperature plays an important role when calculating the limiting molecular weight of gases that a celestial body can retain. Titan has a much colder average atmospheric temperature of about 95 K (-178.15°C or -288.67°F), in contrast to Earth's much warmer climate. The temperature of an atmosphere affects the speed at which gas molecules move; colder temperatures result in slower moving molecules.

When the kinetic energy of the gas molecules is lower due to reduced temperatures, the gravitational pull of the moon or planet can more easily retain these gases. For Titan, this means that its cooler atmosphere allows it to hold onto lighter gases than Earth could at the same temperatures, a fascinating aspect for those studying planetary atmospheres and possible extraterrestrial life. By using the temperature in the formula to calculate the limiting molecular weight, \(M = \frac {2kT}{v_{e}^{2}}\), students can understand how Titan's temperature influences which gases remain in its atmosphere.
Limiting Molecular Weight
Limiting molecular weight is the threshold below which a gas will escape from a planet's or moon's atmosphere due to the thermal speed of its molecules. It combines concepts of both temperature and gravity: the higher the temperature or the lower the gravity, the lighter the molecules that can escape from the atmosphere.

The calculation of Titan's limiting molecular weight involves the escape speed and the atmospheric temperature. The formula \(M = \frac {2kT}{v_{e}^{2}}\) includes the Boltzmann constant (\(k\)), representing the relationship between temperature and kinetic energy, and the square of the escape velocity (\(v_{e}^{2}\)). The lower escape velocity on Titan allows it to retain molecules of a lower molecular weight. With a calculated escape speed, the limiting molecular weight suggests what types of gases are likely to be found in Titan's atmosphere. Despite its distance from the Sun and colder environment, these factors contribute to Titan having a dense atmosphere with a diverse chemical composition.

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