It is desirable to be able to measure the radial velocity of stars (using the Doppler effect) to an accuracy of \(1 \mathrm{~km} / \mathrm{s}\) or better. One complication is that radial velocities refer to the motion of the star relative to the Sun, while the observations are made using a telescope on the Earth. Is it important to take into account the motion of the Earth around the Sun? Is it important to take into account the Earth's rotational motion? To answer this question, you will have to calculate the Earth's orbital speed and the speed of a point on the Earth's equator (the part of the Earth's surface that moves at the greatest speed because of the planet's rotation). If one or both of these effects are of importance, how do you suppose astronomers compensate for them?

Short Answer

Expert verified
Given that both Earth's rotation and orbital motion can result in velocities greater than \(1 \mathrm{~km} / \mathrm{s}\), it suggests both effects should be considered when measuring a star's radial velocity to an accuracy of \(1 \mathrm{~km} / \mathrm{s}\).

Step by step solution

01

Calculating the Earth's Orbital Speed

The Earth's orbital speed is calculated using the formula \( v = \frac{2\pi r}{T} \), where \(r\) is the radius of Earth's orbit (approximately 1 AU or 1.496 x \(10^{11}\) meters) and \(T\) is the period of one revolution around the sun (1 year or about 3.156 x \(10^{7}\) seconds).
02

Calculating the Earth's Equatorial Speed

The equatorial speed is calculated using similar reasoning as the orbital speed, but this time we're describing a rotation about the Earth's axis. The formula is \( v = \frac{2\pi R}{t} \), where \( R \) is Earth's radius (about 6.378 x \(10^{6}\) meters), and \( t \) is the rotation period (1 day or 86,400 seconds).
03

Comparing the calculated speeds to the accuracy requirement

Once the equatorial and orbital speeds are computed, they should be compared to the desired accuracy of the radial velocity measurement, which is about \(1 \mathrm{~km} / \mathrm{s}\). If either of the calculated speeds is around this value or higher, it would mean that it's crucial to consider that speed when obtaining measurements.
04

Discussion on Possible Astronomical Compensations

If the speeds proved to be significant, we'd expect astronomers to take steps to compensate for them. This could involve knowing the precise position and speed of Earth at the time of observation and adjusting for these effects mathematically. Many modern astronomical software automatically perform these calculations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Doppler Effect
The Doppler effect is a phenomenon used to measure the velocity of an object relative to an observer by observing the change in frequency or wavelength of a wave emitted by the object. For instance, when a star moves towards Earth, the wavelengths of the light it emits compress, making them bluer (blue shift); conversely, when a star moves away, wavelengths stretch, making them redder (red shift). This effect is a cornerstone of astronomical measurements, particularly when attempting to gauge the radial velocity of a star with respect to the Sun.

To ascertain the radial velocity of a star with precision, adjustments for the Doppler effect are essential. Astronomers usually account for the relative motion of Earth when they observe stars because this motion affects the frequency of the incoming light. This interplay between observation and motion is delicate; even the Earth's own speed can influence the observed data significantly, which is why understanding both Earth's orbital and equatorial speeds is paramount.
Earth's Orbital Speed
Understanding Earth's orbital speed is critical when measuring the radial velocity of stars to an accuracy of 1 km/s or better. Earth orbits the Sun at an average speed calculated by the formula
\( v = \frac{2\pi r}{T} \), where \( r \) is the radius of Earth's orbit and \( T \) is the time taken to complete one orbit. Given that Earth orbits at approximately 30 km/s, it's clear that this speed must be taken into account when measuring the radial velocity of stars.

This orbital motion induces a Doppler shift in the observed spectra of stars, and to obtain an accurate measurement, it's crucial to adjust for Earth's motion around the Sun. Astronomical observations are generally corrected for this orbital speed to ensure that the radial velocities reflect the stars' movements relative to the Sun and not contaminated by Earth's orbital dynamics.
Earth's Equatorial Speed
Similarly, Earth's equatorial speed is a vital component to consider for high-precision astronomical measurements. The formula \( v = \frac{2\pi R}{t} \) is used to measure this speed, with \( R \) representing Earth's radius and \( t \) the time of one rotation— one day. Earth's rotation at the equator moves the surface at about 0.5 km/s. Despite being half the resolution of the target accuracy for radial velocity measurements, it's still significant enough to influence observations.

Astronomers need to take into account this rotational speed particularly when making observations from telescopes situated on Earth's surface. Adjustments can be made to account for the observer's motion due to the planet's rotation. For highly precise measurements required in modern astronomy, even the smallest speed can result in a noticeable Doppler shift. Thus, compensation for the equatorial speed is as important as compensating for the orbital speed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the average distance from the Sun to Neptune in parsecs. Compared to Neptune, how many times farther away from the Sun is Proxima Centauri?

In the spectrum of a particular star, the Balmer line \(\mathrm{H}_{\alpha}\) has a wavelength of \(656.15 \mathrm{~nm}\). The laboratory value for the wavelength of \(\mathrm{H}_{\alpha}\) is \(656.28 \mathrm{~nm}\). (a) Find the star's radial velocity. (b) Is this star approaching us or moving away? Explain. (c) Find the wavelength at which you would expect to find \(\mathrm{H}_{\alpha}\) in the spectrum of this star, given that the laboratory wavelength of \(\mathrm{H}_{\alpha}\) is \(486.13 \mathrm{~nm}\). (d) Do your answers depend on the distance from the Sun to this star? Why or why not?

Use the Starry Night Enthusiast'M program to examine the nearby stars. Click on Favourites \(>\) Stars > Local Neighborhood and Stop time. Select View \(>\) Feet to hide the spacesuit image. Center this view upon the Sun by opening the Find pane and doubleclicking on Sun. You are now \(16.41\) light years from the Sun, looking at the labeled nearby stars. Increase current elevation to about 70,000 light-years using the button on the toolbar below the Viewing Location box (an upward-pointing triangle) to see these nearby stars within the Milky Way Galaxy. You can rotate the galaxy by placing the mouse cursor over the image and holding down the Shift key while holding down the mouse button and moving the mouse. (On a twobutton mouse, hold down the left mouse button). Decrease current elevation to a distance of about 100 light-years from the Sun to return to the solar neighborhood. Again, you can rotate this swarm of stars by holding down the Shift key while holding down the mouse button and moving the mouse. Open the Info pane. If you click the mouse while the cursor is over a star, you will see the star's apparent magnitude as seen from Earth in the Other Data layer and its distance from the Sun in the Position in Space layer of the Info pane. (a) Select at least 5 stars within 50 light-years of the Sun and note their names, apparent magnitudes, luminosities, and distances from the Sun in a list. Which of these stars would be visible from Earth with the naked eye from a dark location? Which are visible with the naked eye from a brightly lit city? (Hint: The naked eye can see stars as faint as apparent magnitude \(m=+6\) from a dark location, but only as faint as \(m=+4\) from an inner city.) (b) Increase current elevation once more to about 1000 light- years from Earth and locate at least 5 stars that are further than 500 light- years from the Sun, making a list of these stars, their names, apparent magnitudes, luminosities and distances from the Sun. Which of these stars are visible from Earth with the naked eye from a dark location? Are the naked-eye stars more likely to be giants or supergiants, or are they more likely to be main-sequence stars? Explain your answer.

Why are measurements of stellar parallax difficult to make? What are the advantages of making these measurements from orbit?

Why does it take at least six months to make a measurement of a star's parallax?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free