What is the Schwarzschild radius of a black hole whose mass is that of (a) the Earth, (b) the Sun, (c) the supermassive black hole in NGC 4261 (Section 22-5)? In each case, also calculate what the density would be if the matter were spread uniformly throughout the volume of the event horizon.

Short Answer

Expert verified
The Schwarzschild radius and density obtained depend on the mass of each celestial body. You obtain them using the described formulas in the steps provided above.

Step by step solution

01

Calculate Schwarzschild radius

For each of the given masses (Earth, Sun, supermassive black hole in NGC 4261), calculate the Schwarzschild radius using the formula \(r_s = \frac{2GM}{c^2}\). Note that the mass should be in kilograms, the gravitational constant G in \(m^3 kg^{-1} s^{-2}\) and the speed of light c in \(m s^{-1}\). The result will be in meters.
02

Calculate the volume

Next, calculate the volume of the sphere with radius \(r_s\) using the formula \(V = \frac{4}{3}πr_s^3\).
03

Calculate Density

Finally, calculate the density using the formula \(\rho = \frac{m}{V}\) where m is the mass of the black hole (in Kg) and V is the volume (in cubic meters).

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