Chapter 23: Problem 41
Show that the form of Kepler's third law stated in Box 23-2, \(P^{2}=4 \pi^{2} a^{3} / G\left(M+\mathrm{M}_{\odot}\right)\), is equivalent to \(M=r v^{2} / G\), provided the orbit is a circle. (Hint: The mass of the Sun (M \(\mathrm{M}_{\odot}\) ) is much less than the mass of the Galaxy inside the Sun's orbit (M).)
Short Answer
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Key Concepts
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