4 Calculate the mass density of radiation \(\left(\rho_{\mathrm{rad}}\right)\) in each of the following situations, and explain whether each situation is matter-dominated or radiation-dominated: (a) the photosphere of the Sun \(\left(T=5800 \mathrm{~K}, \rho_{\mathrm{m}}=3 \times 10^{-4} \mathrm{~kg} / \mathrm{m}^{3}\right) ;(\) b \()\) the center of the Sun \(\left(T=1.55 \times 10^{7} \mathrm{~K}, \rho_{\mathrm{m}}=1.6 \times 10^{5} \mathrm{~kg} / \mathrm{m}^{3}\right)\); (c) the solar corona \(\left(T=2 \times 10^{6} \mathrm{~K}, \rho_{\mathrm{m}}=5 \times 10^{-13} \mathrm{~kg} / \mathrm{m}^{3}\right)\).

Short Answer

Expert verified
In the photosphere (\(\rho_{rad} = 1.77 \times 10^{-6} kg/m^3\)) and the center of the Sun (\(\rho_{rad} = 2.38 \times 10^{3} kg/m^3\)), matter dominates respectively. In the solar corona (\(\rho_{rad} = 0.12 kg/m^3\)), the radiation dominates.

Step by step solution

01

Photosphere of the Sun

First, calculate the radiation density using the Steven-Boltzmann law for the photosphere of the Sun where \(T=5800 K\) and \(\rho_{m} = 3 \times 10^{-4} kg/m^3\). Using the formula \(\rho_{rad} = aT^4\), this results in \(\rho_{rad} = 7.56 \times 10^{-16} (5800)^4 = 1.77 \times 10^{-6} kg/m^3\). Comparing this with \(\rho_{m}\), this situation is matter-dominated since \(\rho_{m} > \rho_{rad}\).
02

Center of the Sun

Next, look at the center of the Sun where \(T = 1.55 \times 10^{7} K\) and \(\rho_{m} = 1.6 \times 10^{5} kg/m^3\). Using the Steven-Boltzmann law again, \(\rho_{rad} = 7.56 \times 10^{-16} * (1.55 \times 10^{7})^4 = 2.38 \times 10^{3} kg/m^3\). This situation is still matter-dominated, as \(\rho_{m} > \rho_{rad}\).
03

The Solar Corona

Finally, consider the solar corona where \(T = 2 \times 10^{6} K\) and \(\rho_{m} = 5 \times 10^{-13} kg/m^3\). Here, \(\rho_{rad} = 7.56 \times 10^{-16} * (2 \times 10^{6})^4 = 0.12 kg/m^3\). The solar corona is radiation-dominated since \(\rho_{rad} > \rho_{m}\).

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