A comet orbits the Sun with a sidereal period of \(64.0\) years. (a) Find the semimajor axis of the orbit. (b) At aphelion, the comet is \(31.5\) AU from the Sun. How far is it from the Sun at perihelion?

Short Answer

Expert verified
The semi-major axis of the orbit is approximately 52 AU. The comet is approximately 72.5 AU from the Sun at perihelion.

Step by step solution

01

Solving Part (a)

According to Kepler's Third Law, the square of the period of orbit \(T\) is proportional to the cube of the semi-major axis \(a\). In units where \(G = 4\pi^2 \), the average distance \(a\) from the Sun (in AU) and the period \(T\) (in Earth years) satisfy the equation \( T^2 = a^3 \). We can rearrange this equation to solve for \(a\), obtaining \( a = \sqrt[3]{T^2} \). Substituting \( T = 64.0 \) years, we find that the semi-major axis is approximately \( a = \sqrt[3]{(64.0)^2} \approx 52 \) AU.
02

Solving Part (b)

The distance of the comet from the Sun at aphelion is given as 31.5 AU, which we'll denote as \( r_a \). The semi-major axis that we found in Part (a) is the average of the distances at aphelion and perihelion, i.e., \( a = (r_a + r_p) / 2 \), where \( r_p \) is the distance at perihelion. If we solve this equation for \( r_p \), we get \( r_p = 2a - r_a \). Substituting the actual values \( a = 52 \) AU and \( r_a = 31.5 \) AU, we find that the comet is approximately \( r_p = 2*52 - 31.5 \approx 72.5 \) AU from the Sun at perihelion.

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Most popular questions from this chapter

Imagine a planet like the Earth orbiting a star with 4 times the mass of the Sun. If the semimajor axis of the planet's orbit is \(1 \mathrm{AU}\), what would be the planet's sidereal period? (Hint: Use Newton's form of Kepler's third law. Compared with the case of the Earth orbiting the Sun, by what factor has the quantity \(m_{1}+m_{2}\) changed? Has \(a\) changed? By what factor must \(P^{2}\) change?)

How did the models of Aristarchus and Copernicus explain the retrograde motion of the planets?

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Explain why the semimajor axis of a planet's orbit is equal to the average of the distance from the Sun to the planet at perihelion (the perihelion distance) and the distance from the Sun to the planet at aphelion (the aphelion distance).

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