Two polarizing sheets \(P_{1}\) and \(P_{2}\) are placed together with their transmission axes oriented at an angle \(\theta\) to each other. What is \(\theta\) when only \(25 \%\) of the maximum transmitted light intensity passes through them?

Short Answer

Expert verified
The angle \( \theta \) between the transmission axes of the polarizing sheets when only \(25\%\) of the maximum transmitted light intensity passes through them is \(60^\circ\).

Step by step solution

01

Write Malus' Law formula for transmitted intensity

Malus' Law states that the transmitted intensity I of light through two polarizers is given by the formula: \[ I=I_{0} \cos^2{\theta} \] where: - \(I_0\) is the maximum intensity of the light (when the angle between the polarizers is 0), - θ is the angle between the transmission axes of the polarizers and - I is the transmitted light intensity.
02

Calculate the ratio between the transmitted intensity and the maximum intensity

We are given that 25% of the maximum transmitted light intensity passes through the polarizers. So, we can write the ratio of transmitted intensity (I) to the maximum intensity (\(I_0\)) as follows: \[ \frac{I}{I_0} = 0.25 \]
03

Substitute the intensity ratio into Malus' Law formula and solve for θ

Using the given ratio between the transmitted intensity and the maximum intensity, we can substitute it into the Malus' Law formula: \[ 0.25 = \cos^2{\theta} \] Now, we need to find θ. First, take the square root of both sides of the equation: \[ \sqrt{0.25} = \cos{\theta} \] \[ 0.5 = \cos{\theta}\] Finally, find the inverse cosine (arccos) of 0.5 to calculate θ: \[ \theta = \arccos{0.5} \]
04

Calculate the angle θ

Using a calculator or online tool, we can find the angle θ as follows: \[ \theta = \arccos{0.5} = 60^\circ\] So, the angle between the transmission axes of the polarizers is 60° when only 25% of the maximum transmitted light intensity passes through them.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free