Write the complete decay equation in the complete \(_{Z}^{A} \mathrm{X}_{N}\) notation for the beta \(\left(\beta^{-}\right)\) decay of \(^{3} \mathrm{H}\) (tritium), a manufactured isotope of hydrogen used in some digital watch displays, and manufactured primarily for use in hydrogen bombs.

Short Answer

Expert verified
\[ _{1}^{3}\mathrm{H}_{2} \rightarrow _{2}^{3}\mathrm{He}_{1} + \beta^{-} + \bar{\nu} \]

Step by step solution

01

Identify tritium's atomic number and mass number

Tritium (\(^3\mathrm{H}\)) is an isotope of hydrogen. Hydrogen has an atomic number (Z) of 1. The mass number (A) of tritium is given as 3. So, tritium can be written as \(_{1}^{3}\mathrm{H}_{2}\), where N (number of neutrons) is 2.
02

Determine the resulting isotope after beta decay

In beta decay, a neutron converts into a proton. This increases the atomic number by 1 while keeping the mass number constant. For tritium, the atomic number will increase from 1 to 2. This new atomic number corresponds to the element helium. Since the mass number remains constant at 3, the resulting isotope after beta decay is \(_{2}^{3}\mathrm{He}_{1}\).
03

Write the complete decay equation

Now, we can write the decay equation using the \(_{Z}^{A}\mathrm{X}_{N}\) notation. The initial element is tritium \(_{1}^{3}\mathrm{H}_{2}\), and the resulting element is \(_{2}^{3}\mathrm{He}_{1}\). Since a high-energy electron (beta particle, \(\beta^{-}\)) and an antineutrino (\(\bar{\nu}\)) are released during the decay, we can include them in the equation. The complete decay equation is: \[ _{1}^{3}\mathrm{H}_{2} \rightarrow _{2}^{3}\mathrm{He}_{1} + \beta^{-} + \bar{\nu} \] This is the desired decay equation for the beta decay of tritium in the \(_{Z}^{A}\mathrm{X}_{N}\) notation.

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