Chapter 3: Problem 40
An oil slick on water is 120 nm thick and illuminated by white light incident perpendicular to its surface. What color does the oil appear (what is the most constructively reflected wavelength), given its index of refraction is \(1.40 ?\)
Short Answer
Expert verified
The most constructively reflected wavelength of light for an oil slick with a thickness of 120 nm and an index of refraction of 1.40 is 672 nm, which corresponds to a red color. Therefore, the oil appears red in color.
Step by step solution
01
Set up the equation for constructive interference
Write the equation for constructive interference in thin films:
\(2 * t * n = m * \lambda\)
02
Substitute the given values
Substitute the given thickness of the oil slick (t = 120 nm) and its index of refraction (n = 1.40) into the equation:
\(2 * 120 * 1.40 = m * \lambda\)
03
Simplify the equation
Simplify the equation to find the product of m and the wavelength:
\(336 = m * \lambda\)
04
Choose an appropriate value for m
In order to find the most constructive interference for visible light, choose a value for m that yields a wavelength between 400 nm and 700 nm. If m = 1, we would have:
\(336 = 1 * \lambda\)
This corresponds to a wavelength of 336 nm, which falls outside the range of visible light.
For m = 2, we have:
\(336 = 2 * \lambda\)
Solving for λ, we get:
\(\lambda = \frac{336}{2} = 168\) nm
This wavelength also falls outside the range of visible light.
Now, let's try with m = 3:
\(336 = 3 * \lambda\)
Solving for λ, we get:
\(\lambda = \frac{336}{3} = 112\) nm
This wavelength is still outside the range of visible light. Finally, let's try m = 4:
\(336 = 4 * \lambda\)
Solving for λ, we get:
\(\lambda = \frac{336}{4} = 84\) nm
This wavelength is also outside the range of visible light. However, we have made an error when implementing the constructive interference equation for thin-film interference.
The correct equation is:
\(t = \frac{m * \lambda}{4 * n}\)
05
Correct the equation and solve for λ
Using the correct equation for constructive interference in thin films, substitute the given thickness of the oil slick (t = 120 nm) and its index of refraction (n = 1.40):
\(120 = \frac{m * \lambda}{4 * 1.40}\)
06
Solve for λ
Rearrange the equation to solve for m * λ:
\(120 * 4 * 1.40 = m * \lambda\)
\(672 = m * \lambda\)
We can now attempt m values again.
For m = 1:
\(672 = 1 * \lambda\)
\(\lambda = 672\) nm
This wavelength is within the range of visible light, and corresponds to a red color.
Therefore, the most constructively reflected wavelength of light is 672 nm, and the oil appears red in color.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Constructive Interference
Constructive interference occurs in waves when two or more coherent waves coincide in phase, which means their crests and troughs line up perfectly. This synchronization causes the wave amplitudes to add up, resulting in a wave of greater amplitude. In the context of thin-film interference, such as an oil slick on water, constructive interference happens when reflected light waves from the top and bottom surfaces of the film combine to enhance each other.
Imagine tossing two stones into a still pond some distance apart. The ripples from each disturbance move outward until they meet. If the crests of the ripples from one stone align with the crests from the other, the water rises higher than the ripples from any single stone, illustrating constructive interference.
In terms of mathematical analysis, when light of wavelength \( \lambda \) reflects off the layers of the thin film at certain angles and the path difference is a multiple of \( \lambda \) (specifically, \( m \lambda \) where \( m \) is an integer), constructive interference is achieved. This can lead to observable colorful patterns or even determine the perceived color of the object, as seen with the oil slick exercise.
Imagine tossing two stones into a still pond some distance apart. The ripples from each disturbance move outward until they meet. If the crests of the ripples from one stone align with the crests from the other, the water rises higher than the ripples from any single stone, illustrating constructive interference.
In terms of mathematical analysis, when light of wavelength \( \lambda \) reflects off the layers of the thin film at certain angles and the path difference is a multiple of \( \lambda \) (specifically, \( m \lambda \) where \( m \) is an integer), constructive interference is achieved. This can lead to observable colorful patterns or even determine the perceived color of the object, as seen with the oil slick exercise.
Index of Refraction
The index of refraction, often denoted as \( n \) , is a dimensionless number that describes how light travels through a medium relative to its speed in a vacuum. It is defined as the ratio of the speed of light in a vacuum to the speed of light in the material: \( n = \frac{c}{v} \), where \( c \) is the speed of light in a vacuum, and \( v \) is the speed of light in the medium. Every material has a characteristic index of refraction.
The index of refraction is pivotal in thin-film interference because it affects the phase of the reflected light. When light passes from a medium with a lower index of refraction to a higher one (like air to oil), it undergoes a phase shift of 180 degrees, which is equivalent to a half-wavelength (\( \frac{\lambda}{2} \) ). This must be taken into account when calculating the constructive interference condition in a thin film, such as the oil slick in the exercise, to predict the observed color.
The index of refraction is pivotal in thin-film interference because it affects the phase of the reflected light. When light passes from a medium with a lower index of refraction to a higher one (like air to oil), it undergoes a phase shift of 180 degrees, which is equivalent to a half-wavelength (\( \frac{\lambda}{2} \) ). This must be taken into account when calculating the constructive interference condition in a thin film, such as the oil slick in the exercise, to predict the observed color.
Visible Light Spectrum
The visible light spectrum consists of the range of electromagnetic radiation that is visible to the human eye. This range is typically described as having wavelengths between approximately 400 nanometers (nm) and 700 nm. Each wavelength within this spectrum corresponds to a different color, beginning with violet at the shortest wavelengths and ending with red at the longest wavelengths.
Colors of the Visible Spectrum
- Violet: 400–450 nm
- Blue: 450–495 nm
- Green: 495–570 nm
- Yellow: 570–590 nm
- Orange: 590–620 nm
- Red: 620–700 nm