Find the minimum thickness of a soap bubble that appears red when illuminated by white light perpendicular to its surface. Take the wavelength to be \(680 \mathrm{nm}\), and assume the same index of refraction as water.

Short Answer

Expert verified
The minimum thickness that the soap bubble needs to have to appear red when illuminated by white light perpendicular to its surface is approximately \(255 \text{nm}\).

Step by step solution

01

Identify the Given

The given parameters are the wavelength of the light \(\lambda = 680 \text{nm} = 680 \times 10^{-9} m\) and the index of refraction of the soap bubble film is considered the same as that of water which is \(n = 1.33\). We also know that we're looking for the minimum thickness, which means we take \(m = 1\) for the first order of interference.
02

Apply the Condition for Constructive Interference

The constructive interference condition in thin films is given by \(2nt = m\lambda\). Substituting the given values and \(m = 1\) into the equation, we get \(2 \times 1.33 \times t = 1 \times 680 \times 10^{-9}\) m. By rearranging the equation, we can solve for the thickness of the film, \(t\).
03

Calculate the Thickness of the Soap Bubble

\(\Rightarrow t = \frac{680 \times 10^{-9} m}{2 \times 1.33}\). If we perform these calculations, we obtain \(t \approx 255 \times 10^{-9} m\) or when expressed in nanometers, \(t \approx 255 \text{nm}\). This is the minimum thickness that the soap bubble needs to have to appear red when illuminated by white light perpendicular to its surface.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constructive Interference
Constructive interference occurs when two or more waves superimpose to produce a combined amplitude that is greater than that of the individual waves. This phenomenon is particularly important in the context of thin film interference, such as what we see with soap bubbles and oil slicks. When light reflects off the top and bottom surfaces of a thin film and then recombines, if the waves are 'in phase'—meaning the peaks of the waves align with each other—they amplify the light's intensity, resulting in bright, vivid colors.

For constructive interference in thin films, the thickness of the film plays a crucial role, as it determines whether the reflected light waves will be in phase. To identify these conditions, one uses equations that consider the wavelength of light and the refractive index of the film material, ultimately determining the film thickness for which the constructive interference will occur for a specific color of light.
Optical Path Difference
Optical path difference (OPD) is critical to understanding thin film interference. It represents the difference in the path lengths that two light waves travel before recombining. However, simply measuring the physical distance isn't enough—we must also account for the difference in speed of light in various mediums by using the index of refraction. The OPD helps us to calculate whether waves will undergo constructive or destructive interference.

In the case of a soap bubble, the OPD includes the thickness of the film multiplied by the index of refraction, effectively 'stretching' the path the light travels inside the film compared to the same distance in a vacuum. For constructive interference, the OPD must be a multiple of the light's wavelength, adjusted for phase changes upon reflection. This principle guides us in solving for the minimum thickness that produces the desired interference effect.
Wavelength
The wavelength of light is the distance over which the wave's shape repeats. It is a crucial factor in interference patterns because it determines the color of light we see. In thin film interference, light of a specific wavelength will constructively or destructively interfere depending on the film's thickness.

Visible light includes wavelengths approximately from 400 nm (violet) to 700 nm (red). In our exercise, the wavelength given for the red light is 680 nm. This number is an essential component for calculating the thickness of a film that would cause red light to undergo constructive interference, leading to the appearance of a red hue in the soap bubble when observed at a specific angle and under white light illumination.
Index of Refraction
The index of refraction, denoted as 'n', is a dimensionless number that describes how light propagates through a medium compared to the speed of light in a vacuum. It is defined by the ratio of the speed of light in a vacuum to the speed of light in the medium. The index of refraction is a fundamental property that affects the bending of light at interfaces and the optical path length within materials.

In the context of thin film interference, the index of refraction of the film determines how much the light slows down as it passes through and affects the optical path difference. A higher index of refraction means a greater reduction in the speed of light within the material, and therefore, a larger optical path length for the same physical film thickness. In our exercise, the soap bubble is considered to have the same index of refraction as water, n = 1.33, which is a key variable for computing the minimum thickness for the red appearance of the bubble.

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Most popular questions from this chapter

The interference pattern of a He-Ne laser light \((\lambda=632.9 \mathrm{nm})\) passing through two slits \(0.031 \mathrm{mm}\) apart is projected on a screen \(10.0 \mathrm{m}\) away. Determine the distance between the adjacent bright fringes.

A good quality camera "lens" is actually a system of lenses, rather than a single lens, but a side effect is that a reflection from the surface of one lens can bounce around many times within the system, creating artifacts in the photograph. To counteract this problem, one of the lenses in such a system is coated with a thin layer of material \((n=1.28)\) on one side. The index of refraction of the lens glass is \(1.68 .\) What is the smallest thickness of the coating that reduces the reflection at \(640 \mathrm{nm}\) by destructive interference? (In other words, the coating's effect is to be optimized for \(\lambda=640 \mathrm{nm} .)\)

Fifty-one narrow slits are equally spaced and separated by \(0.10 \mathrm{mm}\). The slits are illuminated by blue light of wavelength \(400 \mathrm{nm} .\) What is angular position of the twenty-fifth secondary maximum? What is its peak intensity in comparison with that of the primary maximum?

A thin film with \(n=1.32\) is surrounded by air. What is the minimum thickness of this film such that the reflection of normally incident light with \(\lambda=500 \mathrm{nm}\) is minimized?

A thin wedge filled with air is produced when two flat glass plates are placed on top of one another and a slip of paper is inserted between them at one edge. Interference fringes are observed when monochromatic light falling vertically on the plates are seen in reflection. Is the first fringe near the edge where the plates are in contact a bright fringe or a dark fringe? Explain.

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