Explain the importance of the Young double-slit experiment.

Short Answer

Expert verified
The importance of the Young double-slit experiment lies in its demonstration of the wave-particle duality of light and the interference of light waves. The experiment involves a monochromatic light source passing through two parallel slits, which then diffracts and interferes, creating a pattern of alternating light and dark bands on a screen. This interference pattern provides evidence for the wave nature of light, as particles would not create such a pattern. Furthermore, the experiment has contributed to the development of quantum mechanics by demonstrating that both light and particles like electrons display both wave-like and particle-like properties.

Step by step solution

01

Introduce the Young double-slit experiment

The Young double-slit experiment, named after Thomas Young who first performed it in 1801, is a landmark experiment which demonstrates the wave-particle duality of light. In this experiment, a light source passes through a pair of thin parallel slits, then the light diffracts and ultimately forms a pattern on a screen. This pattern is due to the interference of light waves.
02

Explain the experimental setup

A monochromatic light source (light of single wavelength) is directed towards a barrier with two slits, separated by a certain distance. As the light passes through these slits, it diffracts and spreads out in all directions. These light waves then overlap in the region behind the slits and interfere. Finally, a screen is placed at a specific distance from the double slits to capture the pattern generated by this interference of light waves.
03

Explain the interference pattern

When the light waves from the two slits overlap, they interfere with each other, producing a pattern of alternating light and dark bands on the screen. This is called an interference pattern. The light bands occur when the light waves from the two slits are in phase (constructive interference) and reinforce each other, while the dark bands occur when the light waves are out of phase (destructive interference) and cancel each other out.
04

Calculate the position of bright and dark bands

The position of the bright and dark bands can be calculated by using the interference formula: \[n\lambda = d\sin\theta\] Where: - \(n\) is an integer representing the order of the bright band (0, 1, 2, ...) - \(\lambda\) is the wavelength of the light source - \(d\) is the distance between the two slits - \(\theta\) is the angular position of the bright band on the screen For dark bands, the formula is slightly different: \[(n+\frac{1}{2})\lambda = d\sin\theta\]
05

Explain the significance of the Young double-slit experiment

The significance of the Young double-slit experiment lies in the fact that it provides evidence for the wave nature of light, as particles would not create an interference pattern. Furthermore, the experiment demonstrates the wave-particle duality of light, as light exhibits both wave-like and particle-like properties. This idea was later extended to particles such as electrons, leading to the development of quantum mechanics. Thus, the Young double-slit experiment plays a foundational role in our understanding of the behavior of light and quantum mechanics.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The cutoff wavelength for the emission of 7. photoelectrons from a particular surface is \(500 \mathrm{nm}\). Find the maximum kinetic energy of the ejected photoelectrons when the surface is illuminated with light of wavelength \(600 \mathrm{nm}\).

The momentum of light, as it is for particles, is exactly reversed when a photon is reflected straight back from a mirror, assuming negligible recoil of the mirror. The change in momentum is twice the photon's incident momentum, as it is for the particles. Suppose that a beam of light has an intensity \(1.0 \mathrm{kW} / \mathrm{m}^{2}\) and falls on a \(-2.0-\mathrm{m}^{2}\) area of a mirror and reflects from it. (a) Calculate the energy reflected in 1.00 s. (b) What is the momentum imparted to the mirror? (c) Use Newton's second law to find the force on the mirror. (d) Does the assumption of norecoil for the mirror seem reasonable?

Show that Wien's displacement law results from Planck's radiation law. (Hint: substitute \(x=h c / \lambda k T\) and write Planck's law in the form \(I(x, T)=A x^{5} /\left(e^{x}-1\right)\) where \(A=2 \pi(k T)^{5} /\left(h^{4} c^{3}\right) .\) Now, for fixed \(T,\) find the position of the maximum in \(I(x, T)\) by solving for \(x\) in the equation \(d I(x, T) / d x=0 .)\),

X-rays form ionizing radiation that is dangerous to living tissue and undetectable to the human eye. Suppose that a student researcher working in an X-ray diffraction laboratory is accidentally exposed to a fatal dose of radiation. Calculate the temperature increase of the researcher under the following conditions: the energy of X-ray photons is \(200 \mathrm{keV}\) and the researcher absorbs \(4 \times 10^{13}\) photons per each kilogram of body weight during the exposure. Assume that the specific heat of the student's body is \(0.83 \mathrm{kcal} / \mathrm{kg} \cdot \mathrm{K}\).

What is the longest wavelength that light can have if it is to be capable of ionizing the hydrogen atom in its ground state?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free