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Chapter 9: Problem 11

In sodium chloride, how many \(\mathrm{Cl}^{-}\) atoms are "nearest neighbors" of \(\mathrm{Na}^{+}\) ? How many \(\mathrm{Na}^{+}\) atoms are "nearest neighbors" of \(\mathrm{Cl}^{-}\) ?

Short Answer

Expert verified
In sodium chloride, each Na+ ion has 6 nearest neighbor Cl- atoms, and each Cl- ion has 6 nearest neighbor Na+ atoms.

Step by step solution

01

Determine the sodium chloride lattice structure

Sodium chloride (NaCl) has a face-centered cubic (fcc) lattice structure. Each Na+ cation is surrounded by six Cl- anions, and each Cl- anion is surrounded by six Na+ cations. The Na+ and Cl- ions form an alternating checkerboard pattern.
02

Find the coordination numbers of Na+ and Cl- ions

In the fcc lattice structure, the coordination number is 6 for both Na+ and Cl- ions. This means each Na+ ion is surrounded by 6 Cl- ions, and each Cl- ion is surrounded by 6 Na+ ions as nearest neighbors.
03

Answer the questions

In sodium chloride, 6 Cl- atoms are nearest neighbors of Na+, and 6 Na+ atoms are nearest neighbors of Cl-.

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