Chapter 9: Problem 83
Potassium fluoride (KF) is a molecule formed by an ionic bond. At equilibrium separation the atoms are \(r_{0}=0.255 \mathrm{nm}\) apart. Determine the electrostatic potential energy of the atoms. The electron affinity of \(F\) is 3.40 \(\mathrm{eV}\) and the ionization energy of \(\mathrm{K}\) is \(4.34 \mathrm{eV}\). Determine dissociation energy. (Neglect the energy of repulsion.)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.