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Chapter 1: Problem 39

The unit of pressure in the SI system is the pascal. What would be the SI name for 1 one-thousandth of a pascal?

Short Answer

Expert verified
Answer: 1 millipascal (1 mPa)

Step by step solution

01

Understand the SI prefix system

In the SI (International System of Units) system, there are various prefixes used to represent decimal multiples and submultiples of a unit. In this case, we will look for the prefix that represents one-thousandth (1/1000).
02

Identify the appropriate SI prefix

The prefix for one-thousandth is "milli" (m), which represents a factor of 10^{-3}.
03

Convert pascal to millipascal

Now that we know the SI prefix for one-thousandth is "milli", we can convert 1 pascal to millipascal. To do this, multiply the value of pascal by the milli factor (\times10^{-3}): 1\,\text{Pascal} \times 10^{-3} = 1\,\text{millipascal}
04

Provide the final SI name

The SI name for 1 one-thousandth of a pascal is 1 millipascal (1 mPa).

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Most popular questions from this chapter

A speed of \(7 \mathrm{~mm} / \mu \mathrm{s}\) is equal to: a) \(7000 \mathrm{~m} / \mathrm{s}\) b) \(70 \mathrm{~m} / \mathrm{s}\) c) \(7 \mathrm{~m} / \mathrm{s}\) d) \(0.07 \mathrm{~m} / \mathrm{s}\)

What is the sum of \(5.786 \cdot 10^{3} \mathrm{~m}\) and \(3.19 \cdot 10^{4} \mathrm{~m} ?\) a) \(6.02 \cdot 10^{23} \mathrm{~m}\) c) \(8.976 \cdot 10^{3} \mathrm{~m}\) b) \(3.77 \cdot 10^{4} \mathrm{~m}\) d) \(8.98 \cdot 10^{3} \mathrm{~m}\)

A pilot decides to take his small plane for a Sunday afternoon excursion. He first flies north for 155.3 miles, then makes a \(90^{\circ}\) turn to his right and flies on a straight line for 62.5 miles, then makes another \(90^{\circ}\) turn to his right and flies 47.5 miles on a straight line. a) How far away from his home airport is he at this point? b) In which direction does he need to fly from this point on to make it home in a straight line? c) What was the farthest distance he was away from the home airport during the trip?

Sketch the vectors with the components \(\vec{A}=\left(A_{x}, A_{y}\right)=\) \((30.0 \mathrm{~m},-50.0 \mathrm{~m})\) and \(\vec{B}=\left(B_{x}, B_{y}\right)=(-30.0 \mathrm{~m}, 50.0 \mathrm{~m}),\) and find the magnitudes of these vectors.

Find the magnitude and direction of each of the following vectors, which are given in terms of their \(x\) - and \(y\) -components: \(\vec{A}=(23.0,59.0),\) and \(\vec{B}=(90.0,-150.0)\)
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