A uniform solid sphere of mass \(M\) and radius \(R\) is rolling without sliding along a level plane with a speed \(v=3.00 \mathrm{~m} / \mathrm{s}\) when it encounters a ramp that is at an angle \(\theta=23.0^{\circ}\) above the horizontal. Find the maximum distance that the sphere travels up the ramp in each case: a) The ramp is frictionless, so the sphere continues to rotate with its initial angular speed until it reaches its maximum height. b) The ramp provides enough friction to prevent the sphere from sliding, so both the linear and rotational motion stop (instantaneously).

Short Answer

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Question: A solid sphere of mass m and radius R is rolling without slipping on a flat surface with a linear speed of 3.00 m/s. The sphere then starts to roll up a ramp inclined at an angle θ. Calculate the maximum distance the sphere would travel up the ramp in two cases: a) a frictionless ramp, and b) a ramp with friction. Answer: To calculate the maximum distance the sphere travels up the ramp in both cases, we first determine the initial linear and rotational kinetic energies of the sphere. Next, we use conservation of energy principles to set up equations for each case. The maximum distance in cases a) and b) can be found by dividing their corresponding maximum heights (h_a and h_b) by the sine of the angle θ: distance_a = h_a / sin(θ) distance_b = h_b / sin(θ)

Step by step solution

01

Calculate the initial rotational and linear kinetic energies

To start, let's calculate the initial linear and rotational kinetic energies of the sphere while it's rolling at 3.00 m/s on the flat surface. The linear kinetic energy can be calculated using: KE_linear = (1/2)mv^2 Additionally, since the sphere is rolling without slipping, we can find the moment of inertia, I, of the sphere as: I = (2/5)mR^2 The initial rotational kinetic energy can then be calculated using: KE_rotational = (1/2)Iω^2 We know that v = Rω, therefore: ω = v/R
02

Calculate total initial energy

The total initial energy (E_initial) is the sum of the linear and rotational kinetic energies: E_initial = KE_linear + KE_rotational By substituting the formulae for KE_linear and KE_rotational, we can write: E_initial = (1/2)mv^2 + (1/2)((2/5)mR^2)(v/R)^2
03

Set up conservation of energy equation for each case

First, let's analyze both cases separately: a) Frictionless ramp In this case, the linear kinetic energy is conserved, but the rotational kinetic energy remains the same as the sphere continues to rotate with its initial angular speed. To find the maximum distance the sphere travels up the ramp, we can equate the initial energy with the potential energy gained: E_initial = mgh b) Frictional ramp In this case, both linear and rotational motion stop, and all the kinetic energy is converted into potential energy: E_initial = mgh
04

Calculate maximum height and distance in both cases

For case a), we have E_initial = mgh. Using this formula, we can find the maximum height (h) in terms of the given variables: h_a = E_initial/(mg) For case b), we have the same formula for maximum height: h_b = E_initial/(mg) Now, we need to calculate the maximum distance traveled up the ramp in both cases. To do this, we'll use the trigonometric relationship: distance = h / sin(θ) The maximum distance for case a) is: distance_a = h_a / sin(θ) And the maximum distance for case b) is: distance_b = h_b / sin(θ)

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