Satellites in low orbit around the Earth lose energy from colliding with the gases of the upper atmosphere, causing them to slowly spiral inward. What happens to their kinetic energy as they fall inward?

Short Answer

Expert verified
Answer: As the satellite loses energy and spirals inward, its kinetic energy increases to maintain the conservation of mechanical energy. The satellite gains tangential velocity as it moves into an orbit closer to the Earth, resulting in the increase in kinetic energy.

Step by step solution

01

Understand gravitational potential energy

Gravitational potential energy (U) is the energy an object possesses due to its position relative to a massive body, such as Earth. It is given by the formula: U = -G * m * M / r where G is the gravitational constant, m is the mass of the satellite, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite.
02

Understand kinetic energy

Kinetic energy (K) is the energy of an object due to its motion. It can be calculated using the formula: K = (1/2) * m * v^2 where m is the mass of the satellite, and v is its velocity.
03

Understand conservation of mechanical energy

The total mechanical energy (E) of a system is the sum of its kinetic energy (K) and potential energy (U) - that is, E = K + U. According to the conservation of mechanical energy principle, the total mechanical energy of a system remains constant if no external force acts upon it. In this case, the external force is the collisions with the atmosphere. We'll need to calculate the changes in total mechanical energy due to these collisions.
04

Calculate the change in gravitational potential energy

As the satellite spirals inward, its distance (r) from the Earth's center decreases. This means that the gravitational potential energy of the satellite (U) becomes less negative, or in other words, it increases. Since the mass of the satellite and Earth and the gravitational constant do not change, the change in U is directly related to the change in r.
05

Calculate the change in kinetic energy

In order for the total mechanical energy to be conserved, the increase in gravitational potential energy must be matched by an increase in the satellite's kinetic energy. To maintain a stable orbit, as the satellite moves inward, its tangential velocity must increase. Using the formula K = (1/2) * m * v^2, the increase in kinetic energy can be calculated.
06

Summarize the changes in the satellite's kinetic energy

As the satellite loses energy due to collisions with the Earth's upper atmosphere, it spirals inward, leading to an increase in its gravitational potential energy. To conserve mechanical energy, the satellite's kinetic energy also increases, as it gains tangential velocity while moving into an orbit closer to the Earth. Thus, the satellite's kinetic energy increases as it falls inward.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The distances from the Sun at perihelion and aphelion for Pluto are \(4410 \cdot 10^{6} \mathrm{~km}\) and \(7360 \cdot 10^{6} \mathrm{~km},\) respectively. What is the ratio of Pluto's orbital speed around the Sun at perihelion to that at aphelion?

You have been sent in a small spacecraft to rendezvous with a space station that is in a circular orbit of radius \(2.5000 \cdot 10^{4} \mathrm{~km}\) from the Earth's center. Due to a mishandling of units by a technician, you find yourself in the same orbit as the station but exactly halfway around the orbit from it! You do not apply forward thrust in an attempt to chase the station; that would be fatal folly. Instead, you apply a brief braking force against the direction of your motion, to put you into an elliptical orbit, whose highest point is your present position, and whose period is half that of your present orbit. Thus, you will return to your present position when the space station has come halfway around the circle to meet you. Is the minimum radius from the Earth's center-the low point \(-\) of your new elliptical orbit greater than the radius of the Earth \((6370 \mathrm{~km})\), or have you botched your last physics problem?

Standing on the surface of a small spherical moon whose radius is \(6.30 \cdot 10^{4} \mathrm{~m}\) and whose mass is \(8.00 \cdot 10^{18} \mathrm{~kg}\) an astronaut throws a rock of mass 2.00 kg straight upward with an initial speed \(40.0 \mathrm{~m} / \mathrm{s}\). (This moon is too small to have an atmosphere.) What maximum height above the surface of the moon will the rock reach?

Newton was holding an apple of mass \(100 . \mathrm{g}\) and thinking about the gravitational forces exerted on the apple by himself and by the Sun. Calculate the magnitude of the gravitational force acting on the apple due to (a) Newton, (b) the Sun, and (c) the Earth, assuming that the distance from the apple to Newton's center of mass is \(50.0 \mathrm{~cm}\) and Newton's mass is \(80.0 \mathrm{~kg}\).

A planet with a mass of \(7.00 \cdot 10^{21} \mathrm{~kg}\) is in a circular orbit around a star with a mass of \(2.00 \cdot 10^{30} \mathrm{~kg} .\) The planet has an orbital radius of \(3.00 \cdot 10^{10} \mathrm{~m}\). a) What is the linear orbital velocity of the planet? b) What is the period of the planet's orbit? c) What is the total mechanical energy of the planet?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free