Careful measurements of local variations in the acceleration due to gravity
can reveal the locations of oil deposits. Assume that the Earth is a uniform
sphere of radius \(6370 \mathrm{~km}\) and density \(5500 . \mathrm{kg} /
\mathrm{m}^{3},\) except that there is a spherical region of radius \(1.00
\mathrm{~km}\) and density \(900 . \mathrm{kg} / \mathrm{m}^{3}\) whose center is
at a depth of \(2.00 \mathrm{~km} .\) Suppose you are standing on the surface of
the Earth directly above the anomaly with an instrument capable of measuring
the acceleration due to gravity with great precision. What is the ratio of the
acceleration due to gravity that you measure compared to what you would have
measured had the density been \(5500 . \mathrm{kg} / \mathrm{m}^{3}\)
everywhere? (Hint: Think of this as a superposition problem involving two
uniform spherical masses, one with a negative density.)