In a binary star system consisting of two stars of equal mass, where is the gravitational potential equal to zero? a) exactly halfway between the stars b) along a line bisecting the line connecting the stars c) infinitely far from the stars d) none of the above

Short Answer

Expert verified
Answer: a) exactly halfway between the stars

Step by step solution

01

Recall the formula for gravitational potential

The gravitational potential at a point in space due to a single point mass is given by: \(V(r) = \frac{-GM}{r}\) Where \(V(r)\) is the gravitational potential, \(G\) is the gravitational constant, \(M\) is the mass of the point mass, and \(r\) is the distance from the mass to the point where the potential is being measured. The gravitational potential due to a system of multiple point masses can be found using the principle of superposition, by simply adding the potentials due to each mass at the point of interest.
02

Use the principle of superposition to find regions where the gravitational potential is zero

In the case of a binary star system with two stars of equal mass, we have: \(V_{total}(r) = V_1(r) + V_2(r)\) Where \(V_1(r)\) and \(V_2(r)\) are the gravitational potentials due to the two stars. Since the stars have equal mass, \(M_1 = M_2 = M\), and we can write: \(V_{total}(r) = \frac{-GM}{r_1} + \frac{-GM}{r_2}\) We are looking for regions where the total gravitational potential is equal to zero, so we set \(V_{total}(r)\) to 0: \(0 = \frac{-GM}{r_1} + \frac{-GM}{r_2}\)
03

Analyze the equation for gravitational potential and compare it to the answer choices

In the equation \(0 = \frac{-GM}{r_1} + \frac{-GM}{r_2}\), the total gravitational potential will be equal to zero if and only if the individual potentials are equal: \(\frac{-GM}{r_1} = \frac{-GM}{r_2}\) This implies that \(r_1 = r_2\), which means that the point where the potential is zero must be equidistant from both stars. Let's compare this conclusion to the given answer choices: a) exactly halfway between the stars: This choice aligns with our conclusion that the point must be equidistant from both stars, which means it would be halfway between the stars. b) along a line bisecting the line connecting the stars: It is not enough to say that the point must lie along the line connecting the stars since this line contains points that are not equidistant from the stars. c) infinitely far from the stars: This choice does not align with our conclusion that the point must be equidistant from both the stars, and it would not be physically possible for the potential to be zero at an infinite distance from them. d) none of the above: Since option (a) matches our conclusion, this answer choice is incorrect. Overall, the correct answer is: a) exactly halfway between the stars

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The Moon causes tides because the gravitational force it exerts differs between the side of the Earth nearest the Moon and that farthest from the Moon. Find the difference in the accelerations toward the Moon of objects on the nearest and farthest sides of the Earth.

The distances from the Sun at perihelion and aphelion for Pluto are \(4410 \cdot 10^{6} \mathrm{~km}\) and \(7360 \cdot 10^{6} \mathrm{~km},\) respectively. What is the ratio of Pluto's orbital speed around the Sun at perihelion to that at aphelion?

Two planets have the same mass, \(M .\) Each planet has a constant density, but the density of planet 2 is twice as high as that of planet \(1 .\) Identical objects of mass \(m\) are placed on the surfaces of the planets. What is the relationship of the gravitational potential energy, \(U_{1},\) on planet 1 to \(U_{2}\) on planet \(2 ?\) a) \(U_{1}=U_{2}\) b) \(U_{1}=\frac{1}{2} U_{2}\) c) \(U_{1}=2 U_{2}\) d) \(U_{1}=8 U_{2}\) e) \(U_{1}=0.794 U_{2}\)

A comet orbiting the Sun moves in an elliptical orbit. Where is its kinetic energy, and therefore its speed, at a maximum, at perihelion or aphelion? Where is its gravitational potential energy at a maximum?

Determine the minimum amount of energy that a projectile of mass \(100.0 \mathrm{~kg}\) must gain to reach a circular orbit \(10.00 \mathrm{~km}\) above the Earth's surface if launched from (a) the North Pole or from (b) the Equator (keep answers to four significant figures). Do not be concerned about the direction of the launch or of the final orbit. Is there an advantage or disadvantage to launching from the Equator? If so, how significant is the difference? Do not neglect the rotation of the Earth when calculating the initial energies.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free