You are in a boat filled with large rocks in the middle of a small pond. You begin to drop the rocks into the water. What happens to the water level of the pond? a) It rises. d) It rises momentarily and then b) It falls. falls when the rocks hit bottom. c) It doesn't change. e) There is not enough information to say.

Short Answer

Expert verified
Answer: b) It falls.

Step by step solution

01

Analyze the initial situation

Initially, there is a boat filled with large rocks in the middle of a pond. The boat is floating, meaning that its weight is balanced by the buoyant force of the water.
02

Understand the concept of buoyant force

Buoyant force is the upward force exerted by a fluid (in this case, water) on a submerged object. It depends on the volume of water displaced by the object. According to Archimedes' principle, the magnitude of this force is equal to the weight of the water displaced by the object.
03

Consider the weight of the boat and rocks

When the boat is filled with rocks, its weight and the weight of the rocks are supported by the buoyant force from the water. This means that the volume of water displaced by the boat is equal to the total weight of the boat and rocks divided by the density of water.
04

Evaluate the effect of dropping rocks into the water

When a rock is dropped into the pond, it sinks to the bottom, displacing the water around it and creating a new buoyant force. The volume of water displaced by the rock is equal to the weight of the rock divided by the density of water.
05

Compare the displacements

Now, we need to compare the volume of water displaced by the rock when it is in the boat to the volume of water displaced when the rock is at the bottom of the pond. If these volumes are equal, then the water level will not change. If the volume displaced by the rock in the boat is greater than when the rock is at the bottom, the water level will fall. If the volume displaced in the boat is smaller, the water level will rise.
06

Determine the displacements

When the rock is in the boat, it contributes to the weight of the boat, and the volume of water displaced is equal to the total weight (boat and rocks) divided by the density of water. When the rock is at the bottom, it only displaces an amount of water equal to its own volume, as its weight no longer contributes to the buoyant force on the boat. Because rocks are typically denser than water, they displace a smaller volume of water when they are at the bottom of the pond compared to their contribution to the displacement of the boat when they are on it.
07

Conclude the effect on water level

Since the volume of water displaced by the rock is greater when it is in the boat than when it is at the bottom of the pond, the water level will fall when the rocks are dropped into the water. The correct answer is: b) It falls.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate the ratio of the lifting powers of helium (He) gas and hydrogen (H \(_{2}\) ) gas under identical circumstances. Assume that the molar mass of air is \(29.5 \mathrm{~g} / \mathrm{mol}\).

A beaker is filled with water to the rim. Gently placing a plastic toy duck in the beaker causes some of the water to spill out. The weight of the beaker with the duck floating in it is a) greater than the weight before adding the duck. b) less than the weight before adding the duck. c) the same as the weight before adding the duck. d) greater or less than the weight before the duck was added, depending on the weight of the duck.

The Hindenburg, the German zeppelin that caught fire in 1937 while docking in Lakehurst, New Jersey, was a rigid duralumin-frame balloon filled with \(2.000 \cdot 10^{5} \mathrm{~m}^{3}\) of hydrogen. The Hindenburg's useful lift (beyond the weight of the zeppelin structure itself) is reported to have been \(1.099 \cdot 10^{6} \mathrm{~N}(\) or \(247,000 \mathrm{lb}) .\) Use \(\rho_{\text {air }}=1.205 \mathrm{~kg} / \mathrm{m}^{3}, \rho_{\mathrm{H}}=\) \(0.08988 \mathrm{~kg} / \mathrm{m}^{3}\) and \(\rho_{\mathrm{He}}=0.1786 \mathrm{~kg} / \mathrm{m}^{3}\) a) Calculate the weight of the zeppelin structure (without the hydrogen gas). b) Compare the useful lift of the (highly flammable) hydrogen-filled Hindenburg with the useful lift the Hindenburg would have had had it been filled with (nonflammable) helium, as originally planned.

An open-topped tank completely filled with water has a release valve near its bottom. The valve is \(1.0 \mathrm{~m}\) below the water surface. Water is released from the valve to power a turbine, which generates electricity. The area of the top of the tank, \(A_{\mathrm{p}}\) is 10 times the cross-sectional area, \(A_{\mathrm{y}}\) of the valve opening. Calculate the speed of the water as it exits the valve. Neglect friction and viscosity, In addition, calculate the speed of a drop of water released from rest at \(h=1.0 \mathrm{~m}\) when it reaches the elevation of the valve, Compare the two speeds.

In a horizontal water pipe that narrows to a smaller radius, the velocity of the water in the section with the smaller radius will be larger. What happens to the pressure? a) The pressure will be the same in both the wider and narrower sections of the pipe. b) The pressure will be higher in the narrower section of the pipe. c) The pressure will be higher in the wider section of the pipe d) It is impossible to tell.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free