Pendulum A has a bob of mass \(m\) hung from a string of length \(I_{i}\) pendulum \(B\) is identical to \(A\) except its bob has mass \(2 m\). Compare the frequencies of small oscillations of the two pendulums.

Short Answer

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Question: Compare the frequencies of small oscillations of two pendulums: Pendulum A with a mass m and length l, and Pendulum B with a mass of 2m and the same length l. Answer: The frequencies of small oscillations of pendulums A and B are equal.

Step by step solution

01

Formula for frequency of small oscillations

The formula for the frequency of small oscillations of a simple pendulum is given by: \[f = \frac{1}{2\pi}\sqrt{\frac{g}{l}}\] where f is the frequency, g is the acceleration due to gravity, and l is the length of the pendulum.
02

Frequency of Pendulum A

For pendulum A, we have a mass m and length \(l_i\). Using the formula from step 1, the frequency of pendulum A will be: \[f_A = \frac{1}{2\pi}\sqrt{\frac{g}{l_i}}\]
03

Frequency of Pendulum B

Since Pendulum B is identical to Pendulum A except for having a mass of 2m, its length is also \(l_i\), and the frequency of Pendulum B will be given by the same formula: \[f_B = \frac{1}{2\pi}\sqrt{\frac{g}{l_i}}\]
04

Compare the frequencies

Now, we can compare the frequencies of both pendulums. Since both pendulum A and pendulum B have the same length, their frequencies will be the same (since the mass does not affect the frequency in this case) : \[f_A = f_B\] In conclusion, the frequencies of small oscillations of pendulums A and B are equal, despite the difference in mass of their bobs.

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