Two trains are traveling toward each other in still air at \(25.0 \mathrm{~m} / \mathrm{s}\) relative to the ground. One train is blowing a whistle at \(300 .\) Hz. The speed of sound is \(343 \mathrm{~m} / \mathrm{s}\). a) What frequency is heard by a man on the ground facing the whistle-blowing train? b) What frequency is heard by a man on the other train?

Short Answer

Expert verified
Answer: The frequency heard by a man on the ground is approximately 323.90 Hz, and the frequency heard by a man on the other train is approximately 347.80 Hz.

Step by step solution

01

Calculate the frequency heard by a man on the ground

First, consider the man standing on the ground. Since he is not moving, his speed (\(v_0\)) will be 0. The train with the whistle is approaching the observer, so its speed (\(v_s\)) is -25.0 m/s. Using the given values and the Doppler effect equation: $$f' = 300 \frac{343}{343 + (-25)}$$ Now, solve the equation $$f' = 300 \frac{343}{318} \approx 323.90 \,\text{Hz}$$
02

Calculate the frequency heard by a man on the other train

Now let's find the frequency heard by the man on the other train. This time, both \(v_0\) and \(v_s\) will be the same because both the observer and the source are moving toward each other at equal speed. So, \(v_0\) is 25 m/s and \(v_s\) is -25 m/s. Plugging these values into the Doppler effect equation: $$f' = 300 \frac{343 + 25}{343 + (-25)}$$ Now, solve the equation $$f' = 300 \frac{368}{318} \approx 347.80 \,\text{Hz}$$ To conclude: a) The frequency heard by a man on the ground facing the whistle-blowing train is approximately 323.90 Hz. b) The frequency heard by a man on the other train is approximately 347.80 Hz.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Waves
Imagine a ripple spreading out in a pond when you drop a stone into the water. Similarly, sound waves spread out in all directions from the source of the sound. These waves are vibrations of air molecules that our ears interpret as sound. In technical terms, sound waves are longitudinal waves, which means they cause the particles of the medium to vibrate parallel to the direction of wave travel.

Sound waves have specific characteristics such as wavelength, frequency, and amplitude. The frequency of a sound wave, measured in hertz (Hz), is particularly important because it determines the pitch of the sound we hear. The higher the frequency, the higher the pitch will seem. It's crucial to understand that sound waves need a medium like air, water or solids to travel through; they cannot propagate in a vacuum where there are no molecules to vibrate.
Relative Motion
The concept of relative motion is essential when we try to understand the movement of objects from different reference points. It's the difference in motion between two objects, as observed from a specific point of view. For example, if you see a train moving past you while standing still, it has a certain speed in relation to you. However, if you are moving alongside the train at the same speed, from your point of view, the train appears to be still, even though both of you are in motion relative to the ground.

Relative motion plays a vital role in the Doppler effect, where the movement of the source of sound waves and the observer affect the frequency heard. If they are moving towards each other, the frequency increases; if they are moving apart, the frequency decreases. Remember that it's not the actual speed that matters, but the speed relative to each other.
Frequency Change
The concept of 'frequency change' is closely tied to the Doppler effect. When there is relative motion between a source of sound and an observer, the frequency of the sound perceived by the observer changes. In the case of the exercise, the frequency changes because of the movement of the trains towards each other.

The Doppler effect can cause a sound to appear higher in pitch (frequency) if the source is approaching the observer or lower in pitch if the source is moving away. The equation used in the exercise represents how to calculate this effect quantitatively. It's crucial to note that the frequency change observed depends not only on the speed of the source and the observer but also on the speed of sound in the medium through which it travels. In our daily life, we experience the Doppler effect when we hear the siren of an ambulance change in pitch as it drives by us.

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Most popular questions from this chapter

A college student is at a concert and really wants to hear the music, so she sits between two in-phase loudspeakers, which point toward each other and are \(50.0 \mathrm{~m}\) apart. The speakers emit sound at a frequency of \(490 .\) Hz. At the midpoint between the speakers, there will be constructive interference, and the music will be at its loudest. At what distance closest to the midpoint could she also sit to experience the loudest sound?

Standing on the sidewalk, you listen to the horn of a passing car. As the car passes, the frequency of the sound changes from high to low in a continuous manner; that is, there is no abrupt change in the perceived frequency. This occurs because a) the pitch of the sound of the horn changes continuously. b) the intensity of the observed sound changes continuously. c) you are not standing directly in the path of the moving car. d) of all of the above reasons.

A policeman with a very good ear and a good understanding of the Doppler effect stands on the shoulder of a freeway assisting a crew in a 40 -mph work zone. He notices a car approaching that is honking its horn. As the car gets closer, the policeman hears the sound of the horn as a distinct \(\mathrm{B} 4\) tone \((494 \mathrm{~Hz}) .\) The instant the car passes by, he hears the sound as a distinct \(\mathrm{A} 4\) tone \((440 \mathrm{~Hz}) .\) He immediately jumps on his motorcycle, stops the car, and gives the motorist a speeding ticket. Explain his reasoning.

A half-open pipe is constructed to produce a fundamental frequency of \(262 \mathrm{~Hz}\) when the air temperature is \(22^{\circ} \mathrm{C} .\) It is used in an overheated building when the temperature is \(35^{\circ} \mathrm{C} .\) Neglecting thermal expansion in the pipe, what frequency will be heard?

Find the resonance frequency of the ear canal. Treat it as a half-open pipe of diameter \(8.0 \mathrm{~mm}\) and length \(25 \mathrm{~mm}\). Assume that the temperature inside the ear canal is body temperature \(\left(37^{\circ} \mathrm{C}\right)\).

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