Two solid objects, \(A\) and \(B\), are in contact. In which case will thermal energy transfer from \(\mathrm{A}\) to \(\mathrm{B} ?\) a) \(\mathrm{A}\) is at \(20{ }^{\circ} \mathrm{C},\) and \(\mathrm{B}\) is at \(27{ }^{\circ} \mathrm{C}\) b) \(A\) is at \(15^{\circ} \mathrm{C},\) and \(\mathrm{B}\) is at \(15^{\circ} \mathrm{C}\). c) \(\mathrm{A}\) is at \(0{ }^{\circ} \mathrm{C},\) and \(\mathrm{B}\) is at \(-10{ }^{\circ} \mathrm{C}\).

Short Answer

Expert verified
a) A is at 20°C, and B is at 27°C b) A is at 15°C, and B is at 15°C c) A is at 0°C, and B is at -10°C Answer: c) A is at 0°C, and B is at -10°C

Step by step solution

01

Case a: A is at 20°C, and B is at 27°C

In this case, object A has a temperature of 20°C and object B has a temperature of 27°C. Since object B is warmer than object A, thermal energy will not transfer from A to B in this case.
02

Case b: A is at 15°C, and B is at 15°C

In this case, both object A and object B have the same temperature of 15°C. When the temperatures of both objects are equal, there is no temperature difference and thus, no thermal energy transfer occurs between the objects.
03

Case c: A is at 0°C, and B is at -10°C

In this case, object A has a temperature of 0°C, and object B has a temperature of -10°C. Since object A has a higher temperature than object B, thermal energy will transfer from A to B in this case. So, the correct answer is.Option (c) A is at 0°C and B is at -10°C.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Conduction
Heat conduction is a mode of transfer of thermal energy from a region of higher temperature to a region of lower temperature within an object or between objects in direct contact. The fundamental principle guiding heat conduction is that molecules at a higher temperature have more kinetic energy. When these molecules come in contact with cooler molecules, they transfer some of their energy to them, which results in the overall spread of heat. The transfer continues until thermal equilibrium is reached, meaning the objects involved achieve the same temperature.

In the context of the exercise, when solid object A is at a higher temperature than solid object B (case c), the kinetic energy of the molecules in object A is higher. As they are in contact, this energy is transferred to the cooler molecules of object B through the process of heat conduction.
Temperature Difference
The temperature difference between two objects is the driving force for heat conduction. When two objects are at different temperatures and come into contact, the temperature difference creates a 'thermal gradient.' This gradient is what causes thermal energy to move from the hotter object to the cooler one. The greater the temperature difference, the faster the rate of thermal energy transfer.

As afore mentioned in the exercise, case b demonstrates where both objects A and B have no temperature difference. Without a temperature gradient, there is no driving force for the heat to flow, which is why no heat conduction takes place in this scenario. It's critical to remember that thermal energy naturally flows from higher to lower temperatures until it is balanced or equalized across the objects involved.
Thermodynamics
Thermodynamics is the branch of physics that deals with the relationships between heat and other forms of energy. There are four laws of thermodynamics, but the concept of energy transfer is rooted in the first and second laws. The first law, also known as the law of energy conservation, states that energy can neither be created nor destroyed, only transformed from one form to another. This concept is demonstrated with the transfer of thermal energy in conduction.

The second law of thermodynamics states that total entropy, or chaos, of an isolated system can never decrease over time. It suggests that thermal energy transfer from a hot object to a cold one (such as object A to object B when A is warmer), without the input of work, is a spontaneous process that increases the overall entropy of the system. These fundamental principles of thermodynamics are essential to understanding the flow of heat and energy distribution in any system, including the exercise presented.

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Most popular questions from this chapter

a) Suppose a bimetallic strip is constructed of copper and steel strips of thickness \(1.0 \mathrm{~mm}\) and length \(25 \mathrm{~mm},\) and the temperature of the strip is reduced by \(5.0 \mathrm{~K}\). Determine the radius of curvature of the cooled strip (the radius of curvature of the interface between the two strips). b) If the strip is \(25 \mathrm{~mm}\) long, how far is the maximum deviation of the strip from the straight orientation?

The volume of \(1.00 \mathrm{~kg}\) of liquid water over the temperature range from \(0.00^{\circ} \mathrm{C}\) to \(50.0^{\circ} \mathrm{C}\) fits reasonably well to the polynomial function \(V=1.00016-\left(4.52 \cdot 10^{-5}\right) T+\) \(\left(5.68 \cdot 10^{-6}\right) T^{2}\), where the volume is measured in cubic meters and \(T\) is the temperature in degrees Celsius. a) Use this information to calculate the volume expansion coefficient for liquid water as a function of temperature. b) Evaluate your expression at \(20.0^{\circ} \mathrm{C}\), and compare the value to that listed in Table \(17.3 .\)

An aluminum vessel with a volume capacity of \(500 . \mathrm{cm}^{3}\) is filled with water to the brim at \(20 .{ }^{\circ} \mathrm{C} .\) The vessel and contents are heated to \(50 .{ }^{\circ} \mathrm{C} .\) During the heating process, will the water spill over the top, will there be more room for water to be added, or will the water level remain the same? Calculate the volume of water that will spill over or that could be added if either is the case.

A medical device used for handling tissue samples has two metal screws, one \(20.0 \mathrm{~cm}\) long and made from brass \(\left(\alpha_{\mathrm{b}}=18.9 \cdot 10^{-6}{ }^{\circ} \mathrm{C}^{-1}\right)\) and the other \(30.0 \mathrm{~cm}\) long and made from aluminum \(\left(\alpha_{\mathrm{a}}=23.0 \cdot 10^{-6}{ }^{\circ} \mathrm{C}^{-1}\right)\). A gap of \(1.00 \mathrm{~mm}\) exists between the ends of the screws at \(22.0^{\circ} \mathrm{C}\). At what temperature will the two screws touch?

At room temperature, an iron horseshoe, when dunked into a cylindrical tank of water (radius of \(10.0 \mathrm{~cm})\) causes the water level to rise \(0.25 \mathrm{~cm}\) above the level without the horseshoe in the tank. When heated in the blacksmith's stove from room temperature to a temperature of \(7.00 \cdot 10^{2} \mathrm{~K}\) worked into its final shape, and then dunked back into the water, how much does the water level rise above the "no horseshoe" level (ignore any water that evaporates as the horseshoe enters the water)? Note: The linear expansion coefficient for iron is roughly that of steel: \(11 \cdot 10^{-6}{ }^{\circ} \mathrm{C}^{-1}\).

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