Which of the following statements is (are) true? a) When a system does work, its internal energy always decreases. b) Work done on a system always decreases its internal energy. c) When a system does work on its surroundings, the sign of the work is always positive. d) Positive work done on a system is always equal to the system's gain in internal energy. e) If you push on the piston of a gas-filled cylinder, the energy of the gas in the cylinder will increase.

Short Answer

Expert verified
Based on the analysis of the given statements, identify which statements are true and which are false regarding work and internal energy. a) False - When a system does work, its internal energy does not always decrease. b) False - Work done on a system does not always decrease its internal energy. c) True - When a system does work on its surroundings, the sign of the work is always positive. d) False - Positive work done on a system is not always equal to the system's gain in internal energy. e) True - If you push on the piston of a gas-filled cylinder, the energy of the gas in the cylinder will increase.

Step by step solution

01

Statement a)

This statement claims that when a system does work, its internal energy always decreases. According to the first law of thermodynamics, the change in internal energy (∆U) is equal to the heat added to the system (Q) minus the work done by the system (W): ∆U = Q - W. When a system does work (W > 0), it is possible for its internal energy to decrease if the heat added (Q) is less than the work done. However, it is not true in every case since the heat added can be greater than the work done, leading to an increase in internal energy. Therefore, statement a is false.
02

Statement b)

This statement claims that work done on a system always decreases its internal energy. According to the first law of thermodynamics, if work is done on a system, it means that an external force is doing work on the system to increase its internal energy. In this case, the work done (W) is negative. The equation ∆U = Q - W would become: ∆U = Q + |W|. Since both Q and |W| are positive, the internal energy should increase. Therefore, statement b is false.
03

Statement c)

This statement claims that when a system does work on its surroundings, the sign of the work is always positive. According to the sign convention, when a system does work on its surroundings (expands), the work done is considered positive (W > 0). When surroundings do work on the system (compresses), the work done is considered negative (W < 0). Therefore, statement c is true.
04

Statement d)

This statement claims that positive work done on a system is always equal to the system's gain in internal energy. Positive work done on a system means it's done by the surroundings leading to an increase in the system's internal energy. But the first law of thermodynamics (∆U = Q - W) tells us that the change in internal energy depends on both the heat added (Q) and the work done (W) on the system. If positive work is done on the system, it can contribute to an increase in internal energy but it is not always equal to the total gain in internal energy because the heat added (Q) will also affect the internal energy. Therefore, statement d is false.
05

Statement e)

This statement claims that if you push on the piston of a gas-filled cylinder, the energy of the gas in the cylinder will increase. When you push the piston of a gas-filled cylinder, you are performing work on the system which is the gas inside the cylinder. As a result of this work, the internal energy of the gas in the cylinder will increase (provided that there is no heat loss during this process). Therefore, statement e is true. In conclusion: a) False b) False c) True d) False e) True

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You were lost while hiking outside wearing only a bathing suit. a) Calculate the power radiated from your body, assuming that your body's surface area is about \(2.00 \mathrm{~m}^{2}\) and your skin temperature is about \(33.0^{\circ} \mathrm{C} .\) Also, assume that your body has an emissivity of 1.00 . b) Calculate the net radiated power from your body when you were inside a shelter at \(20.0^{\circ} \mathrm{C}\). c) Calculate the net radiated power from your body when your skin temperature dropped to \(27.0^{\circ} \mathrm{C}\).

When an immersion glass thermometer is used to measure the temperature of a liquid, the temperature reading will be affected by an error due to heat transfer between the liquid and the thermometer. Suppose you want to measure the temperature of \(6.00 \mathrm{~mL}\) of water in a Pyrex glass vial thermally insulated from the environment. The empty vial has a mass of \(5.00 \mathrm{~g}\). The thermometer you use is made of Pyrex glass as well and has a mass of \(15.0 \mathrm{~g}\), of which \(4.00 \mathrm{~g}\) is the mercury inside the thermometer. The thermometer is initially at room temperature \(\left(20.0^{\circ} \mathrm{C}\right) .\) You place the thermometer in the water in the vial and, after a while, you read an equilibrium temperature of \(29.0^{\circ} \mathrm{C} .\) What was the actual temperature of the water in the vial before the temperature was measured? The specific heat capacity of Pyrex glass around room temperature is \(800 . J /(\mathrm{kg} \mathrm{K})\) and that of liquid mercury at room temperature is \(140 . \mathrm{J} /(\mathrm{kg} \mathrm{K})\)

How would the rate of heat transfer between a thermal reservoir at a higher temperature and one at a lower temperature differ if the reservoirs were in contact with a 10 -cm-long glass rod instead of a 10 -m-long aluminum rod having an identical cross-sectional area?

The thermal conductivity of fiberglass batting, which is 4.0 in thick, is \(8.0 \cdot 10^{-6} \mathrm{BTU} /\left(\mathrm{ft}^{\circ} \mathrm{F} \mathrm{s}\right) .\) What is the \(R\) value (in \(\left.\mathrm{ft}^{2}{ }^{\circ} \mathrm{F} \mathrm{h} / \mathrm{BTU}\right) ?\)

In one of your rigorous workout sessions, you lost \(150 \mathrm{~g}\) of water through evaporation. Assume that the amount of work done by your body was \(1.80 \cdot 10^{5} \mathrm{~J}\) and that the heat required to evaporate the water came from your body. a) Find the loss in internal energy of your body, assuming the latent heat of vaporization is \(2.42 \cdot 10^{6} \mathrm{~J} / \mathrm{kg}\). b) Determine the minimum number of food calories that must be consumed to replace the internal energy lost (1 food calorie \(=4186\) J).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free