Assuming the severity of a burn increases as the amount of energy put into the skin increases, which of the following would cause the most severe burn (assume equal masses)? a) water at \(90^{\circ} \mathrm{C}\) b) copper at \(110^{\circ} \mathrm{C}\) c) steam at \(180^{\circ} \mathrm{C}\) d) aluminum at \(100^{\circ} \mathrm{C}\) e) lead at \(100^{\circ} \mathrm{C}\)

Short Answer

Expert verified
Answer: (c) steam at \(180^{\circ} \mathrm{C}\)

Step by step solution

01

Research the specific heat capacities of the materials

We need to look up the specific heat capacities of each material in order to make a comparison. Here are the specific heat capacities of each material listed in the problem: Water: \(4.18 \ \mathrm{J / (g \cdot K)}\) Copper: \(0.385 \ \mathrm{J / (g \cdot K)}\) Steam: \(2.03 \ \mathrm{J / (g \cdot K)}\) Aluminum: \(0.897 \ \mathrm{J / (g \cdot K)}\) Lead: \(0.127 \ \mathrm{J / (g \cdot K)}\)
02

Decide on the temperature difference of each material to skin

Next, we need to decide on the temperature difference for each material. We will assume that the temperature of the skin is \(30^{\circ} \mathrm{C}\). The temperature difference (\(ΔT\)) for each material is: Water: \(60^{\circ} \mathrm{C}\) Copper: \(80^{\circ} \mathrm{C}\) Steam: \(150^{\circ} \mathrm{C}\) Aluminum: \(70^{\circ} \mathrm{C}\) Lead: \(70^{\circ} \mathrm{C}\)
03

Calculate the total energy absorbed by skin for each material

Now, we will calculate the energy absorbed by the skin for each material using the specific heat capacities and temperature differences found in steps 1 and 2: Water: \(Q = 4.18 \times 60 = 250.8 \ \mathrm{J}\) Copper: \(Q = 0.385 \times 80 = 30.8 \ \mathrm{J}\) Steam: \(Q = 2.03 \times 150 = 304.5 \ \mathrm{J}\) Aluminum: \(Q = 0.897 \times 70 = 62.79 \ \mathrm{J}\) Lead: \(Q = 0.127 \times 70 = 8.89 \ \mathrm{J}\)
04

Compare the energy values

We can now compare the calculated energy values to determine which material will cause the most severe burn: Water: \(250.8 \ \mathrm{J}\) Copper: \(30.8 \ \mathrm{J}\) Steam: \(304.5 \ \mathrm{J}\) Aluminum: \(62.79 \ \mathrm{J}\) Lead: \(8.89 \ \mathrm{J}\) We can conclude that, given equal masses, steam at \(180^{\circ} \mathrm{C}\) would cause the most severe burn, as the energy absorbed by the skin is the highest (\(304.5 \ \mathrm{J}\)) among all materials. Therefore, the correct answer is (c) steam at \(180^{\circ} \mathrm{C}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Heat Capacity
Specific heat capacity is a property that describes how much heat energy is needed to raise the temperature of a certain mass of substance by one degree Celsius (or one Kelvin). Formally, it is expressed as joules per gram per degree Celsius \( \mathrm{J / (g \cdot ^{\circ}C)} \).

A substance with a high specific heat capacity can absorb a lot of heat without changing its temperature significantly. This is crucial when considering burn severity, as a material's specific heat capacity influences the amount of energy it can transfer to the skin. For instance, water has a high specific heat capacity \(4.18 \mathrm{J / (g \cdot K)} \), which means it can store and release a large amount of energy, potentially causing more severe burns compared to other materials with a lower specific heat capacity, such as lead \(0.127 \mathrm{J / (g \cdot K)} \).

Understanding specific heat capacity helps us to predict the outcome when different materials at various temperatures come into contact with the skin, by showing how much energy can be transferred and possibly causing burns.
Thermal Energy Transfer
Thermal energy transfer, often referred to as heat transfer, describes the flow of heat energy from a hotter object to a cooler one. There are three methods of heat transfer: conduction, convection, and radiation. In the context of burn severity, we primarily consider conduction, which is the direct transfer of heat through a medium or between objects in physical contact.

If a material at a high temperature comes into contact with skin, thermal energy will be transferred until there is no temperature difference between the two, hence the severity of a burn highly depends on the amount of energy transferred. In the exercise, materials with higher temperatures and specific heat capacities have the potential to transfer more energy to the skin. For example, steam at \(180^\circ \mathrm{C}\) can transfer substantial energy leading to severe burns, particularly because steam can also release latent heat during condensation.
Temperature Difference
Temperature difference, often symbolized as \( \Delta T \), is a critical factor in the severity of burns due to its direct impact on the amount of thermal energy transferred. It's the difference in temperature between two substances - in this case, between the skin and the material in question. The larger the temperature difference, the higher the rate of thermal energy transfer, at least initially.

In our exercise, assuming the skin has a temperature of \(30^\circ \mathrm{C}\), materials with higher initial temperatures like steam will have a larger \( \Delta T \). Hence, they can initially transfer energy more rapidly compared to materials with temperatures closer to that of the skin. The equation for heat transfer used in the step by step solution \(Q = m \cdot c \cdot \Delta T\) takes into account this temperature difference, which is why steam, despite its lower specific heat capacity than water, can cause more severe burns due to its much higher temperature relative to the skin.

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Most popular questions from this chapter

A 1.19-kg aluminum pot contains 2.31 L of water. Both pot and water are initially at \(19.7^{\circ} \mathrm{C} .\) How much heat must flow into the pot and the water to bring their temperature up to \(95.0^{\circ} \mathrm{C}\) ? Assume that the effect of water evaporation during the heating process can be neglected and that the temperature remains uniform throughout the pot and the water.

Arthur Clarke wrote an interesting short story called "A Slight Case of Sunstroke." Disgruntled football fans came to the stadium one day equipped with mirrors and were ready to barbecue the referee if he favored one team over the other. Imagine the referee to be a cylinder filled with water of mass \(60.0 \mathrm{~kg}\) at \(35.0^{\circ} \mathrm{C}\). Also imagine that this cylinder absorbs all the light reflected on it from 50,000 mirrors. If the heat capacity of water is \(4.20 \cdot 10^{3} \mathrm{~J} /\left(\mathrm{kg}^{\circ} \mathrm{C}\right),\) how long will it take to raise the temperature of the water to \(100 .{ }^{\circ} \mathrm{C}\) ? Assume that the Sun gives out \(1.00 \cdot 10^{3} \mathrm{~W} / \mathrm{m}^{2},\) the dimensions of each mirror are \(25.0 \mathrm{~cm}\) by \(25.0 \mathrm{~cm},\) and the mirrors are held at an angle of \(45.0^{\circ}\)

The human body transports heat from the interior tissues, at temperature \(37.0^{\circ} \mathrm{C},\) to the skin surface, at temperature \(27.0^{\circ} \mathrm{C},\) at a rate of \(100 . \mathrm{W}\). If the skin area is \(1.5 \mathrm{~m}^{2}\) and its thickness is \(3.0 \mathrm{~mm}\), what is the effective thermal conductivity, \(\kappa,\) of skin?

You are going to lift an elephant (mass \(\left.=5.0 \cdot 10^{3} \mathrm{~kg}\right)\) over your head \((2.0 \mathrm{~m}\) vertical displacement). a) Calculate the work required to do this. You will lift the elephant slowly (no tossing of the elephant allowed!). If you want, you can use a pulley system. (As you saw in Chapter \(5,\) this does not change the energy required to lift the elephant, but it definitely reduces the force required to do so.) b) How many doughnuts ( 250 food calories each) must you metabolize to supply the energy for this feat?

When an immersion glass thermometer is used to measure the temperature of a liquid, the temperature reading will be affected by an error due to heat transfer between the liquid and the thermometer. Suppose you want to measure the temperature of \(6.00 \mathrm{~mL}\) of water in a Pyrex glass vial thermally insulated from the environment. The empty vial has a mass of \(5.00 \mathrm{~g}\). The thermometer you use is made of Pyrex glass as well and has a mass of \(15.0 \mathrm{~g}\), of which \(4.00 \mathrm{~g}\) is the mercury inside the thermometer. The thermometer is initially at room temperature \(\left(20.0^{\circ} \mathrm{C}\right) .\) You place the thermometer in the water in the vial and, after a while, you read an equilibrium temperature of \(29.0^{\circ} \mathrm{C} .\) What was the actual temperature of the water in the vial before the temperature was measured? The specific heat capacity of Pyrex glass around room temperature is \(800 . J /(\mathrm{kg} \mathrm{K})\) and that of liquid mercury at room temperature is \(140 . \mathrm{J} /(\mathrm{kg} \mathrm{K})\)

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