A car starts from rest and accelerates at \(10.0 \mathrm{~m} / \mathrm{s}^{2}\) How far does it travel in 2.00 s?

Short Answer

Expert verified
Answer: The car travels a distance of 20.0 meters in 2.00 seconds.

Step by step solution

01

List given information

The problem provides us with the following information: - The car starts from rest, meaning its initial velocity is 0: \(v_0 = 0 \mathrm{~m}/\mathrm{s}\) - The car accelerates at a constant rate: \(a = 10.0 \mathrm{~m}/\mathrm{s}^{2}\) - We need to find the distance traveled in a given time: \(t = 2.00 \mathrm{~s}\)
02

Use the kinematic equation to determine the distance traveled

Since we have the initial velocity, acceleration, and time, we can use the following kinematic equation to find the distance traveled: $$ d = v_0t + \frac{1}{2}at^2 $$ This equation states that the distance traveled (d) is equal to the product of the initial velocity (v_0) and time (t) plus one-half the product of the acceleration (a) and the square of the time (t^2).
03

Substitute the given values and solve for the distance

Substitute the given values into the equation: $$ d = (0 \mathrm{~m}/\mathrm{s})(2.00 \mathrm{~s}) + \frac{1}{2}(10.0 \mathrm{~m}/\mathrm{s}^{2})(2.00 \mathrm{~s})^2 $$ Now, simplify the equation and solve for the distance: $$ d = 0 + (10.0 \mathrm{~m}/\mathrm{s}^{2})(4.00 \mathrm{~s}^2)/2 $$ $$ d = (20.0 \mathrm{~m}/\mathrm{s}^{2})(2.00 \mathrm{~s}^2) $$ $$ d = 20.0 \mathrm{~m} $$
04

State the final answer

The car travels a distance of \(20.0\) meters in \(2.00\) seconds.

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