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Chapter 2: Problem 56

An airplane starts from rest and accelerates at \(12.1 \mathrm{~m} / \mathrm{s}^{2}\). What is its speed at the end of a \(500 .-\mathrm{m}\) runway?

Short Answer

Expert verified
Answer: The speed of the airplane at the end of the 500m runway is approximately 110 m/s.

Step by step solution

01

Write down the given values

We know the following values: - Initial velocity (u) = 0 m/s - Acceleration (a) = 12.1 m/s² - Distance (s) = 500 m
02

Use the equation of motion

Now, we will use the equation v² = u² + 2as to find the final velocity (v).
03

Substitute the values and solve for v

Substitute the given values into the equation: v² = (0)² + 2(12.1)(500) Calculating the result: v² = 0 + 2(12.1)(500) v² = 12100 Now, find the square root of 12100 to get the final velocity (v): v = √12100 v ≈ 110 m/s
04

State the final answer

The speed of the airplane at the end of the 500m runway is approximately 110 m/s.

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Most popular questions from this chapter

Two athletes jump straight up. Upon leaving the ground, Adam has half the initial speed of Bob. Compared to Adam, Bob jumps a) 0.50 times as high. b) 1.41 times as high. c) twice as high. d) three times as high. e) four times as high.

Bill Jones has a bad night in his bowling league. When he gets home, he drops his bowling ball in disgust out the window of his apartment, from a height of \(63.17 \mathrm{~m}\) above the ground. John Smith sees the bowling ball pass by his window when it is \(40.95 \mathrm{~m}\) above the ground. How much time passes from the time when John Smith sees the bowling ball pass his window to when it hits the ground?

A car is traveling due west at \(20.0 \mathrm{~m} / \mathrm{s}\). Find the velocity of the car after \(3.00 \mathrm{~s}\) if its acceleration is \(1.0 \mathrm{~m} / \mathrm{s}^{2}\) due west. Assume the acceleration remains constant. a) \(17.0 \mathrm{~m} / \mathrm{s}\) west b) \(17.0 \mathrm{~m} / \mathrm{s}\) east c) \(23.0 \mathrm{~m} / \mathrm{s}\) west d) \(23.0 \mathrm{~m} / \mathrm{s}\) east e) \(11.0 \mathrm{~m} / \mathrm{s}\) south

A car moving at \(60 \mathrm{~km} / \mathrm{h}\) comes to a stop in \(4.0 \mathrm{~s}\). What was its average deceleration? a) \(2.4 \mathrm{~m} / \mathrm{s}^{2}\) b) \(15 \mathrm{~m} / \mathrm{s}^{2}\) c) \(4.2 \mathrm{~m} / \mathrm{s}^{2}\) d) \(41 \mathrm{~m} / \mathrm{s}^{2}\)

An electron, starting from rest and moving with a constant acceleration, travels \(1.0 \mathrm{~cm}\) in \(2.0 \mathrm{~ms}\). What is the magnitude of this acceleration? a) \(25 \mathrm{~km} / \mathrm{s}^{2}\) b) \(20 \mathrm{~km} / \mathrm{s}^{2}\) c) \(15 \mathrm{~km} / \mathrm{s}^{2}\) d) \(10 \mathrm{~km} / \mathrm{s}^{2}\) e) \(5.0 \mathrm{~km} / \mathrm{s}^{2}\)
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