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Chapter 2: Problem 60

A stone is thrown downward with an initial velocity of \(10.0 \mathrm{~m} / \mathrm{s}\). The acceleration of the stone is constant and has the value of the free-fall acceleration, \(9.81 \mathrm{~m} / \mathrm{s}^{2} .\) What is the velocity of the stone after \(0.500 \mathrm{~s} ?\)

Short Answer

Expert verified
Answer: The velocity of the stone after 0.500 seconds is 14.905 m/s.

Step by step solution

01

Note down the given variables

We are given: initial velocity (u) = 10.0 m/s, acceleration (a) = 9.81 m/s^2, and time (t) = 0.500 s.
02

Use the kinematic formula to find the final velocity

Plug in the given values into the equation: Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t) v = 10.0 m/s + (9.81 m/s^2) * (0.500 s)
03

Calculate the final velocity

Now just solve for the final velocity (v): v = 10.0 m/s + (4.905 m/s) v = 14.905 m/s The velocity of the stone after 0.500 s is 14.905 m/s.

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