Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 60

A stone is thrown downward with an initial velocity of \(10.0 \mathrm{~m} / \mathrm{s}\). The acceleration of the stone is constant and has the value of the free-fall acceleration, \(9.81 \mathrm{~m} / \mathrm{s}^{2} .\) What is the velocity of the stone after \(0.500 \mathrm{~s} ?\)

Short Answer

Expert verified
Answer: The velocity of the stone after 0.500 seconds is 14.905 m/s.

Step by step solution

01

Note down the given variables

We are given: initial velocity (u) = 10.0 m/s, acceleration (a) = 9.81 m/s^2, and time (t) = 0.500 s.
02

Use the kinematic formula to find the final velocity

Plug in the given values into the equation: Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t) v = 10.0 m/s + (9.81 m/s^2) * (0.500 s)
03

Calculate the final velocity

Now just solve for the final velocity (v): v = 10.0 m/s + (4.905 m/s) v = 14.905 m/s The velocity of the stone after 0.500 s is 14.905 m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Can an object's acceleration be in the opposite direction to its motion? Explain.

A car travels north at \(30.0 \mathrm{~m} / \mathrm{s}\) for \(10.0 \mathrm{~min}\). It then travels south at \(40.0 \mathrm{~m} / \mathrm{s}\) for \(20.0 \mathrm{~min}\). What are the total distance the car travels and its displacement?

If the acceleration of an object is zero and its velocity is nonzero, what can you say about the motion of the object? Sketch velocity versus time and acceleration versus time graphs for your explanation.

An object is thrown upward with a speed of \(28.0 \mathrm{~m} / \mathrm{s}\). How long does it take it to reach its maximum height?

Starting from rest, a boat increases its speed to \(5.00 \mathrm{~m} / \mathrm{s}\) with constant acceleration. a) What is the boat's average speed? b) If it takes the boat 4.00 s to reach this speed, how far has it traveled?
See all solutions

Recommended explanations on Physics Textbooks

Fields in Physics

Read Explanation

Electromagnetism

Read Explanation

Translational Dynamics

Read Explanation

Mechanics and Materials

Read Explanation

Waves Physics

Read Explanation

Electric Charge Field and Potential

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free