A proposal is submitted for a novel engine that will operate between \(400 . \mathrm{K}\) and \(300 . \mathrm{K}\) a) What is the theoretical maximum efficiency of the engine? b) What is the total entropy change per cycle if the engine operates at maximum efficiency?

Short Answer

Expert verified
Answer: The theoretical maximum efficiency of the engine is 25%, and the total entropy change per cycle if the engine operates at maximum efficiency is 0.

Step by step solution

01

Calculate the theoretical maximum efficiency of the engine

For an engine operating between two temperatures, the theoretical maximum efficiency is given by the Carnot efficiency formula: Efficiency = \(1 - \frac{T_{cold}}{T_{hot}}\) Where \(T_{cold}\) and \(T_{hot}\) are the cold and hot reservoir temperatures, respectively. In this case, we have: \(T_{cold} = 300 \,\mathrm{K}\) and \(T_{hot} = 400 \,\mathrm{K}\) Now we will insert these values into the Carnot efficiency formula: Efficiency = \(1 - \frac{300}{400}\)
02

Simplify the expression

We will simplify the expression to find the efficiency: Efficiency = \(1 - \frac{300}{400} = 1 - \frac{3}{4} = \frac{1}{4}\) So, the theoretical maximum efficiency of the engine is \(\frac{1}{4}\) or 25%.
03

Calculate the total entropy change per cycle

When the engine operates at its maximum efficiency (Carnot efficiency), we know that the total entropy change per cycle is zero: Total entropy change per cycle = 0
04

Write down the answers

a) The theoretical maximum efficiency of the engine is 25%. b) The total entropy change per cycle if the engine operates at maximum efficiency is 0.

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