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Chapter 21: Problem 10

You bring a negatively charged rubber rod close to a grounded conductor without touching it. Then you disconnect the ground. What is the sign of the charge on the conductor after you remove the charged rod? a) negative d) cannot be determined from b) positive the given information c) no charge

Short Answer

Expert verified
Answer: b) positive

Step by step solution

01

Understand grounding and induction

When a negatively charged rubber rod is brought close to a conductor, the electrons in the conductor are repelled by the negatively charged rod and move away from it. This results in a separation of charges within the conductor, with the side closer to the charged rod being positively charged (due to the lack of electrons) and the other side being negatively charged (due to an excess of electrons). This process is called induction.
02

Grounding the conductor

When the conductor is connected to the ground, it allows electrons to flow between the conductor and the ground. In this case, because the side of the conductor farther from the rod is negatively charged (there are excess electrons), those excess electrons will flow into the ground, leaving the conductor with an overall positive charge.
03

Disconnecting the ground and removing the charged rod

Once the ground connection is removed, the flow of electrons between the conductor and the ground stops. This means the conductor retains its positive charge. After removing the charged rod, the conductor remains positively charged.
04

Determine the sign of the charge on the conductor

Based on the previous steps, at the end of the process, the conductor is left with a positive charge. Therefore, the correct answer is: b) positive

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Most popular questions from this chapter

From collisions with cosmic rays and from the solar wind, the Earth has a net electric charge of approximately \(-6.8 \cdot 10^{5} \mathrm{C} .\) Find the charge that must be given to a \(1.0-\mathrm{g}\) object for it to be electrostatically levitated close to the Earth's surface.

Two positive charges, each equal to \(Q\), are placed a distance \(2 d\) apart. A third charge, \(-0.2 Q\), is placed exactly halfway between the two positive charges and is displaced a distance \(x \ll d\) perpendicular to the line connecting the positive charges. What is the force on this charge? For \(x \ll d\), how can you approximate the motion of the negative charge?

Two lightweight metal spheres are suspended near each other from insulating threads. One sphere has a net charge; the other sphere has no net charge. The spheres will a) attract each other. b) exert no net electrostatic force on each other. c) repel each other. d) do any of these things depending on the sign of the charge on the one sphere.

\( \mathrm{~A}-4.0-\mu \mathrm{C}\) charge lies \(20.0 \mathrm{~cm}\) to the right of a \(2.0-\mu \mathrm{C}\) charge on the \(x\) -axis. What is the force on the \(2.0-\mu C\) charge?

A silicon sample is doped with phosphorus at 1 part per \(1.00 \cdot 10^{6} .\) Phosphorus acts as an electron donor, providing one free electron per atom. The density of silicon is \(2.33 \mathrm{~g} / \mathrm{cm}^{3},\) and its atomic mass is \(28.09 \mathrm{~g} / \mathrm{mol}\) a) Calculate the number of free (conduction) electrons per unit volume of the doped silicon. b) Compare the result from part (a) with the number of conduction electrons per unit volume of copper wire (assume each copper atom produces one free (conduction) electron). The density of copper is \(8.96 \mathrm{~g} / \mathrm{cm}^{3},\) and its atomic mass is \(63.54 \mathrm{~g} / \mathrm{mol}\)
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