Two point charges are located at two corners of a rectangle, as shown in the figure. a) What is the electric potential at point \(A ?\) b) What is the potential difference between points \(A\) and \(B ?\)

Short Answer

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Question: Given two point charges \(q_1\) and \(q_2\), the distances from point \(A\) to these charges are \(r_1\) and \(r_2\), and the distances from point \(B\) to these charges are \(r_3\) and \(r_4\). Calculate the electric potential at point \(A\), the electric potential at point \(B\), and the potential difference between points \(A\) and \(B\). Answer: To calculate the electric potential at point \(A\), use the formula: \(V_A = \frac{kq_1}{r_1} + \frac{kq_2}{r_2}\) To calculate the electric potential at point \(B\), use the formula: \(V_B = \frac{kq_1}{r_3} + \frac{kq_2}{r_4}\) To calculate the potential difference between points \(A\) and \(B\), use the formula: \(\Delta V_{AB} = V_A - V_B\)

Step by step solution

01

Write the Formula for Electric Potential

The formula for the electric potential \(V\) at a point due to a point charge \(q\) is: \(V = \frac{kq}{r}\) where - \(k = 8.9875517923 * 10^9 N m^2 / C^2 \) is the electrostatic constant, - \(r\) is the distance between the point and the charge.
02

Calculate the Electric Potential at Point A

To calculate the electric potential at point \(A\), we will consider the contribution of the two point charges and add them together. Let's denote the two point charges as \(q_1\) and \(q_2\), and the distances from point \(A\) to these charges as \(r_1\) and \(r_2\) respectively. Then, the electric potential at point \(A\) can be calculated using the formula: \(V_A = \frac{kq_1}{r_1} + \frac{kq_2}{r_2}\)
03

Calculate the Electric Potential at Point B

To calculate the electric potential at point \(B\), we will again consider the contribution of the two point charges and add them together. Let's denote the distances from point \(B\) to the charges as \(r_3\) and \(r_4\) respectively. The electric potential at point \(B\) can be calculated as: \(V_B = \frac{kq_1}{r_3} + \frac{kq_2}{r_4}\)
04

Calculate the Potential Difference between Points A and B

The potential difference between points \(A\) and \(B\) can be calculated as the difference between the electric potentials at these points: \(\Delta V_{AB} = V_A - V_B\) Now, substitute the values of \(V_A\) and \(V_B\) we found earlier into this equation to get the potential difference between points \(A\) and \(B\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrostatic Constant
Understanding electric potential begins with the electrostatic constant, symbolized by the letter 'k' in equations. It's a fundamental value in electrostatics, representing the force of attraction or repulsion between two point charges in a vacuum. The constant has a value of approximately \(8.9875517923 \times 10^9\) Newton meter squared per Coulomb squared (\( N m^2 / C^2 \)).

When we consider its role in calculating electric potential, the electrostatic constant is a proportionality factor that helps us determine how strong the potential is due to a charge at a given point. It essentially allows us to quantify the influence of a charge in creating an electric field around it. A higher charge or a lower radius will increase the electric potential because the charge impacts a greater force over a smaller area.
Electric Potential Difference
The electric potential difference, often termed 'voltage,' is a measure of the work done by an electric field in moving a charge from one point to another. It's akin to measuring the effort required to move a ball uphill against gravity. Electric potential is energy per unit charge, whereas electric potential difference is the variance in this energy between two points.

In equations, we denote it as \( \Delta V \) and calculate it as the difference in electric potential between two points, expressed as \( \Delta V = V_A - V_B \) in the exercise example. This concept is vitally important because it shows us how potential energy is transformed when a charge moves within an electric field, and it drives the current flow in electrical circuits.
Superposition Principle in Electrostatics
The superposition principle is a key concept in electrostatics, dealing with scenarios where multiple charges are present. It states that the total electric potential at any point is the algebraic sum of the electric potentials due to individual charges.

For example, in our exercise, the electric potential at point A, denoted as \(V_A\), is calculated by summing the potentials due to each point charge separately, following the formula: \(V_A = \frac{kq_1}{r_1} + \frac{kq_2}{r_2}\). This principle greatly simplifies calculations as it allows us to deal with complex charge distributions by considering one charge at a time. It emphasizes that each charge contributes independently to the total potential, and their individual potentials can be simply added together to find the resultant potential.

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Most popular questions from this chapter

Three charges, \(q_{1}, q_{2},\) and \(q_{3},\) are located at the corners of an equilateral triangle with side length of \(1.2 \mathrm{~m}\). Find the work done in each of the following cases: a) to bring the first particle, \(q_{1}=1.0 \mathrm{pC},\) to \(P\) from infinity b) to bring the second particle, \(q_{2}=2.0 \mathrm{pC}\) to \(Q\) from infinity c) to bring the last particle, \(q_{3}=3.0 \mathrm{pC}\) to \(R\) from infinity d) Find the total potential energy stored in the final configuration of \(q_{1}, q_{2},\) and \(q_{3}\)

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