Each of the following pairs of charges are separated by a distance \(d\). Which pair has the highest potential energy? a) \(+5 \mathrm{C}\) and \(+3 \mathrm{C}\) d) \(-5 \mathrm{C}\) and \(+3 \mathrm{C}\) b) \(+5 \mathrm{C}\) and \(-3 \mathrm{C}\) e) All pairs have the \(\begin{array}{ll}\text { c) }-5 \mathrm{C} \text { and }-3 \mathrm{C} & \text { same potential energy. }\end{array}\)

Short Answer

Expert verified
Answer: e) All pairs have the same potential energy.

Step by step solution

01

Calculate potential energy for each pair

To calculate the potential energy for each pair, we will use the formula \(U = k\frac{|q_1q_2|}{d}\), where \(k\) is a constant and can be ignored since we are comparing the values. a) \(U_a = \frac{|(+5C)(+3C)|}{d} = \frac{15C^2}{d}\) d) \(U_d = \frac{|(-5C)(+3C)|}{d} = \frac{15C^2}{d}\) b) \(U_b = \frac{|(+5C)(-3C)|}{d} = \frac{15C^2}{d}\) c) \(U_c = \frac{|(-5C)(-3C)|}{d} = \frac{15C^2}{d}\)
02

Compare potential energies

Comparing the potential energy calculated for all the pairs, we can see that they have the same potential energy, which is \(\frac{15C^2}{d}\). Thus, the answer is: e) All pairs have the same potential energy.

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