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Chapter 24: Problem 13

When working on a piece of equipment, electricians and electronics technicians sometimes attach a grounding wire to the equipment even after turning the device off and unplugging it. Why would they do this?

Short Answer

Expert verified
Answer: Electricians and electronics technicians attach a grounding wire to the equipment after turning it off and unplugging it to ensure that any residual currents or voltages are safely dissipated to the earth, reducing the risk of electric shocks. This precautionary measure is essential for their personal safety and the safety of others in the vicinity while working on electrical systems.

Step by step solution

01

Understand the purpose of grounding

Grounding is a safety measure that is taken to protect individuals from electrical hazards. In electrical systems, grounding connects the neutral points of electrical circuits to the earth, which helps to dissipate any residual voltages or currents that might be present in the system after it has been turned off and unplugged.
02

Identify why grounding is necessary after unplugging the equipment

Residual voltages and currents can still exist in electrical equipment even when it is turned off and unplugged. This can be due to different factors, such as capacitance within the circuit components, inductive and stored energy in transformers or inductors, or static charges. These residual voltages or currents can be potentially harmful and cause electric shocks to anyone working on the equipment. Electrical shocks can lead to injuries or even fatalities.
03

Explain the benefits of using a grounding wire in this case

Attaching a grounding wire to the equipment after turning it off and unplugging it will provide an additional path for residual currents or voltages to flow from the equipment to the earth. This will ensure that any remaining electrical charge is dissipated safely, reducing the risk of electric shocks to the person working on the equipment. By attaching a grounding wire to the equipment, electricians and electronics technicians are taking an important precaution to stay safe while working on electrical systems. This step helps protect against potential electrical hazards and is a crucial practice in ensuring their personal safety and the safety of others in the vicinity.

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Most popular questions from this chapter

The space between the plates of an isolated parallel plate capacitor is filled with a slab of dielectric material. The magnitude of the charge \(Q\) on each plate is kept constant. If the dielectric material is removed from between the plates, the energy stored in the capacitor a) increases. c) decreases. b) stays the same. d) may increase or decrease.

A typical AAA battery has stored energy of about 3400 J. (Battery capacity is typically listed as \(625 \mathrm{~mA} \mathrm{~h}\), meaning that much charge can be delivered at approximately \(1.5 \mathrm{~V}\).) Suppose you want to build a parallel plate capacitor to store this amount of energy, using a plate separation of \(1.0 \mathrm{~mm}\) and with air filling the space between the plates. a) Assuming that the potential difference across the capacitor is \(1.5 \mathrm{~V},\) what must the area of each plate be? b) Assuming that the potential difference across the capacitor is the maximum that can be applied without dielectric breakdown occurring, what must the area of each plate be? c) Is either capacitor a practical replacement for the AAA batterv?

The Earth can be thought of as a spherical capacitor. If the net charge on the Earth is \(-7.8 \cdot 10^{5} \mathrm{C},\) find \((\) a) the capacitance of the Earth and (b) the electric potential energy stored on the Earth's surface

How much energy can be stored in a capacitor with two parallel plates, each with an area of \(64.0 \mathrm{~cm}^{2}\) and separated by a gap of \(1.30 \mathrm{~mm}\), filled with porcelain whose dielectric constant is \(7.0,\) and holding equal and opposite charges of magnitude \(420 . \mu C ?\)

A dielectric slab with thickness \(d\) and dielectric constant \(\kappa=2.31\) is inserted in a parallel place capacitor that has been charged by a \(110 .-\mathrm{V}\) battery and having area \(A=\) \(100, \mathrm{~cm}^{2},\) and separation distance \(d=2.50 \mathrm{~cm}\). a) Find the capacitance, \(C,\) the potential difference, \(V,\) the electric field, \(E,\) the total charge stored on the capacitor \(Q\), and electric potential energy stored in the capacitor, \(U\), before the dielectric material is inserted. b) Find \(C, V, E, Q,\) and \(U\) when the dielectric slab has been inserted and the battery is still connected. c) Find \(C, V, E, Q\) and \(U\) when the dielectric slab is in place and the battery is disconnected.
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