A resistor and a capacitor are connected in series. If a second identical capacitor is connected in series in the same circuit, the time constant for the circuit will a) decrease. b) increase. c) stay the same.

Short Answer

Expert verified
Answer: The time constant in the RC circuit will decrease.

Step by step solution

01

Determine formula for time constant

The formula for the time constant (τ) in an RC circuit is: τ = RC Where R is the resistance and C is the capacitance.
02

Understand the series connection of capacitors

When two capacitors are connected in series, the equivalent capacitance (C_eq) can be found using the formula: 1/C_eq = 1/C₁ + 1/C₂ In this question C₁ = C₂ = C (both capacitors are identical).
03

Calculate the equivalent capacitance after adding the second capacitor in series

Using the formula from the previous step, we can calculate the equivalent capacitance after adding the second capacitor in series: 1/C_eq = 1/C + 1/C 1/C_eq = (2C)/C² So, C_eq = C²/(2C) = C/2 The equivalent capacitance is half of the capacitance of a single capacitor.
04

Determine the new time constant

Now that we know the equivalent capacitance after connecting the second capacitor in series, we can find the new time constant (τ₂) using the formula from step 1: τ₂ = RC_eq = R(C/2) = (1/2)RC
05

Compare the initial and new time constants

Originally, the time constant was τ₁ = RC. After connecting the second capacitor in series, the time constant has become τ₂ = (1/2)RC. Comparing τ₁ and τ₂, we can clearly see that the new time constant has decreased. Therefore, the correct answer is: a) decrease.

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