A square loop, with sides of length \(L\), carries current i. Find the magnitude of the magnetic field from the loop at the center of the loop, as a function of \(i\) and \(L\).

Short Answer

Expert verified
Answer: The magnitude of the magnetic field at the center of the square loop can be expressed as \(B_{total} = \frac{2 \mu_0 i}{\pi L}\), where \(\mu_0\) is the permeability of free space, i is the current flowing in the loop, and L is the length of the sides of the square loop.

Step by step solution

01

Understand Ampere's Law

Ampere's Law states that the circulation of the magnetic field (\(\vec{B}\)) along a closed path is equal to the product of the permeability of free space (\(\mu_0\)) and the enclosed current (\(I_{enc}\)). Mathematically, it is given by: \(\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{enc}\)
02

Break the square loop into four sides

The square loop has four equal sides, each of length L. We will find the magnetic field produced by each side at the center of the loop and then sum up the contributions to find the total magnetic field. Note that for each side, the magnetic field at the center will have a component perpendicular to the plane of the loop.
03

Determine the magnetic field produced by one side

Let's consider one side of the square loop, carrying current i. We label one end of this side as A and the other end as B, placing the center of the loop at point O. Let \(\theta\) be the angle formed between line AO and line BO. Using Ampere's Law and considering symmetry, we can determine the magnetic field produced by the side at the center O. The magnetic field's perpendicular component is given by: \(B_\perp = \frac{\mu_0 i}{4\pi L} \cdot \frac{\sin \theta}{\sin^2 \frac{\theta}{2}}\) In our case, \(\theta = 90°\) (since it's a square loop). Hence, the magnetic field produced by one side can be simplified as: \(B_\perp = \frac{\mu_0 i}{4\pi L} \cdot \frac{\sin 90°}{\sin^2 45°} = \frac{\mu_0 i}{4\pi L} \cdot \frac{1}{\frac{1}{2}} = \frac{\mu_0 i}{2\pi L}\)
04

Find the total magnetic field at the center of the loop

Since the square loop has four sides and the magnetic field produced by each side at the center is equal and perpendicular to the plane of the loop, we simply add up the contributions from all the sides to find the total magnetic field at the center: \(B_{total} = 4 \times B_\perp = 4 \times \frac{\mu_0 i}{2\pi L} = \frac{2 \mu_0 i}{\pi L}\)
05

Express the magnitude of the magnetic field as a function of i and L

The magnitude of the magnetic field at the center of the square loop can be expressed as a function of the current i and the length L as follows: \(B_{total} = \frac{2 \mu_0 i}{\pi L}\) This is our final expression for the magnitude of the magnetic field at the center of the square loop, as a function of i and L.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ampere's Law
Ampere's Law is a foundational principle in electromagnetism that relates the magnetic field around a closed loop to the electric current passing through the loop. The law states that the line integral of the magnetic field \(\vec{B}\) along a closed path is proportional to the electrical current \(I_{enc}\) flowing through the enclosed area. The mathematical expression for Ampere's Law is:\
\
\[\oint \vec{B} \cdot d\vec{l} = \mu_0 I_{enc}\]
\
where \(\mu_0\) is the permeability of free space and \(d\vec{l}\) is an infinitesimal element of the closed path. When we use Ampere's Law to calculate the magnetic field at the center of a square loop, we essentially add up the magnetic effects of the current in each segment of the loop. Despite the complex appearance of the law, it provides a systematic approach for calculating magnetic fields, especially in symmetric configurations, such as loops and coils.
Magnetic Field Calculation
Calculating the magnetic field produced by a current-carrying conductor involves understanding the geometry of the conductor and the position where the field is being calculated. In the case of a square loop, each side contributes a magnetic field component at the center of the loop. By exploiting symmetry and using laws like Ampere's, we can determine that the resultant magnetic field is perpendicular to the plane of the loop.
\
In the case of the square loop, the problem simplifies due to each side producing an identical magnetic field at the center. This allows us to calculate the field for one side and then multiply by the number of sides. The methodical step-by-step solution demonstrated how we harness Ampere's Law to compute \(B_\perp\) for one side and then arrive at the total magnetic field \(B_{total}\) for the whole loop by multiplying by four.
Permeability of Free Space
The permeability of free space, denoted by \(\mu_0\), plays a crucial role in the relationship between electric currents and magnetic fields. This constant represents the extent to which vacuum allows the formation of a magnetic field. Its value is approximately \(4\pi \times 10^{-7} \text{T}·\text{m/A}\), which means that it relates the magnetic field in teslas (T) to the current in amperes (A) and the distance in meters (m).
\
In the solution provided for the square loop, \(\mu_0\) is integral to the final expression for the magnetic field. It is the proportionality constant that makes the relationship precise, allowing for a magnetic field calculation that can be directly tied to the physical characteristics of the loop—the current \(i\) and the side length \(L\).
Current and Magnetic Field Relationship
One of the fundamental tenets of electromagnetism is that electric currents produce magnetic fields. This relationship is exploited when calculating the magnetic field from a current-carrying loop. The direction of the magnetic field produced by a straight current-carrying wire is given by the right-hand rule, and its magnitude is proportional to the current and inversely proportional to the distance from the wire.
\
The square loop example showcases this relationship. Each side of the loop is considered a segment of current that generates a magnetic field at the loop’s center. By calculating the field produced by each segment and considering the direction and proportionality, we obtain the total field resulting from the entire current. The cumulative magnetic field in the center of the loop shows a linear relationship with the current \(i\) and an inverse relationship with the loop side length \(L\).

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Most popular questions from this chapter

The magnetic character of bulk matter is determined largely by electron spin magnetic moments, rather than by orbital dipole moments. (Nuclear contributions are negligible, as the proton's spin magnetic moment is about 658 times smaller than that of the electron.) If the atoms or molecules of a substance have unpaired electron spins, the associated magnetic moments give rise to paramagnetic behavior or to ferromagnetic behavior if the interactions between atoms or molecules are strong enough to align them in domains. If the atoms or molecules have no net unpaired spins, then magnetic perturbations of the electron orbits give rise to diamagnetic behavior. a) Molecular hydrogen gas \(\left(\mathrm{H}_{2}\right)\) is weakly diamagnetic. What does this imply about the spins of the two electrons in the hydrogen molecule? b) What would you expect the magnetic behavior of atomic hydrogen gas (H) to be?

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A long solenoid (diameter of \(6.00 \mathrm{~cm}\) ) is wound with 1000 turns per meter of thin wire through which a current of 0.250 A is maintained. A wire carrying a current of 10.0 A is inserted along the axis of the solenoid. What is the magnitude of the magnetic field at a point \(1.00 \mathrm{~cm}\) from the axis?

You are standing at a spot where the magnetic field of the Earth is horizontal, points due northward, and has magnitude \(40.0 \mu \mathrm{T}\). Directly above your head, at a height of \(12.0 \mathrm{~m},\) a long, horizontal cable carries a steady \(\mathrm{DC}\) current of 500.0 A due northward. Calculate the angle \(\theta\) by which your magnetic compass needle is deflected from true magnetic north by the effect of the cable. Don't forget the sign of \(\theta-\) is the deflection eastward or westward?

A hairpin configuration is formed of two semiinfinite straight wires that are \(2.00 \mathrm{~cm}\) apart and joined by a semicircular piece of wire (whose radius must be \(1.00 \mathrm{~cm}\) and whose center is at the origin of \(x y z\) -coordinates). The top straight wire is along the line \(y=1.00 \mathrm{~cm},\) and the bottom straight wire is along the line \(y=-1.00 \mathrm{~cm} ;\) these two wires are in the left side \((x<0)\) of the \(x y\) -plane. The current in the hairpin is \(3.00 \mathrm{~A},\) and it is directed toward the right in the top wire, clockwise around the semicircle, and to the left in the bottom wire. Find the magnetic field at the origin of the coordinate system.

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