What is a good rule of thumb for designing a simple magnetic coil? Specifically, given a circular coil of radius \(\sim 1 \mathrm{~cm},\) what is the approximate magnitude of the magnetic field, in gauss per amp per turn? (Note: \(1 \mathrm{G}=0.0001 \mathrm{~T}\).) a) \(0.0001 \mathrm{G} /(\mathrm{A}\) -turn \()\) b) \(0.01 \mathrm{G} /(\) A-turn \()\) c) \(1 \mathrm{G} /(\mathrm{A}\) -turn \()\) d) \(100 \mathrm{G} /(\mathrm{A}\) -turn \()\)

Short Answer

Expert verified
Answer: c) 1 G/A⋅turn

Step by step solution

01

Relevant Formula

The magnetic field, B, at the center of a circular coil carrying a current I is given by the following formula, derived from the Biot-Savart law: \(B = \frac{\mu_0 I}{2r}\) where \(\mu_0\) is the permeability of free space (with a value of \(4\pi\times10^{-7} \,\mathrm{Tm/A}\)), I is the current in Amperes, and r is the radius of the coil in meters.
02

Convert units to gauss

We will use the conversion factor: \(1\mathrm{G} = 0.0001\mathrm{T}\) \(1\mathrm{T} = 10000\mathrm{G}\)
03

Calculate the magnetic field per amp per turn

Now, let's calculate the magnetic field for 1 Amp of current and a radius of 1 cm. \(B = \frac{\mu_0 \times 1\,\mathrm{A}}{2 \times 0.01\,\mathrm{m}} = \frac{4\pi\times10^{-7}\,\mathrm{Tm/A}\times 1\,\mathrm{A}}{2\times 0.01\,\mathrm{m}} = 2\pi\times10^{-5}\,\mathrm{T}\) Let's convert the magnetic field to Gauss: \(B = 2\pi\times10^{-5}\,\mathrm{T} \times 10000\,\mathrm{G/T} = 2\pi\times10^{-1}\,\mathrm{G}\) \(B\approx 0.63\,\mathrm{G/A\cdot turn}\)
04

Choose the correct answer

Comparing our computed value to the choices: a) \(0.0001\,\mathrm{G/A\cdot turn}\) b) \(0.01\,\mathrm{G/A\cdot turn}\) c) \(1\,\mathrm{G/A\cdot turn}\) d) \(100\,\mathrm{G/A\cdot turn}\) Our calculated value, approximately \(0.63\,\mathrm{G/A\cdot turn}\), is closest to option (c) \(1 \,\mathrm{G/A\cdot turn}\). Therefore, the correct answer is: c) \(1\,\mathrm{G/A\cdot turn}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Biot-Savart Law
The Biot-Savart Law is a fundamental principle in electromagnetism that describes how currents produce magnetic fields. Primarily used for calculating the magnetic field generated in a space due to any current distribution, it states that each infinitesimal segment of current produces a tiny magnetic field at a point in space, and the total magnetic field is the vector sum of all these tiny fields.

Mathematically, it's expressed as:
\[d\textbf{B} = \frac{\text{μ}_0}{4π} \frac{I d\textbf{l} × \textbf{r̂}}{\textbf{r}^2}\]
where \(d\textbf{B}\) is the differential magnetic field produced by a small segment of current I, \(d\textbf{l}\) is the length element through which the current flows, \( \textbf{r̂} \) is the unit vector from the current element to the point where the field is being calculated, and \(\textbf{r}\) is the distance from the current element to the point.

This law is pivotal for understanding how to calculate the magnetic field around a coil or a wire, which is essential when dealing with electromagnetic applications like motors, generators, and inductors.
Magnetic Field Calculation
When it comes to calculating the magnetic field of a coil, a few key elements determine the characteristics of the field it creates. The type of coil, the number of turns, the current flowing through it, and the coil's radius all come into play.

In the specific case of a circular coil of radius \(r\), carrying current \(I\), the magnetic field at the center of the coil can be calculated using a simplified version of the Biot-Savart Law:
\[B = \frac{\text{μ}_0 I}{2r}\]
This equation reveals that the magnetic field (B) is directly proportional to the current (I) and inversely proportional to the radius (r). The constant \( \text{μ}_0 \) represents the permeability of free space, which is an inherent property of space defining how much resistance there is to the formation of a magnetic field within it. Understanding this calculation is crucial for students because it enables them to determine the strength of the magnetic field generated by different coil configurations, assisting in the design and analysis of electromagnetic devices.
Permeability of Free Space
Permeability of free space, denoted as \( \text{μ}_0 \), is a physical constant that represents how a magnetic field can permeate the vacuum of free space. It is crucial in the calculation of the magnetic field because it forms the proportionality constant in the Biot-Savart Law and Ampère's Law.

The value of permeability of free space is exactly defined as:
\[ \text{μ}_0 = 4π × 10^{-7} \text{ Tm/A} \]
This constant indicates the extent to which a vacuum allows for the passage of magnetic lines of force or flux. The higher the permeability, the less resistance a material or space opposes to the formation of a magnetic field. In everyday units, one Tesla (T) per Ampere (A) per meter (m) is equivalent to the force a charge would feel moving through a magnetic field. Applied to problems like the one in the exercise, knowing the permeability of free space is essential to correctly calculate the strength of the magnetic field produced by current-carrying conductors, such as coils.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two long, straight parallel wires are separated by a distance of \(20.0 \mathrm{~cm}\). Each wire carries a current of \(10.0 \mathrm{~A}\) in the same direction. What is the magnitude of the resulting magnetic field at a point that is \(12.0 \mathrm{~cm}\) from each wire?

A long, straight wire is located along the \(x\) -axis \((y=0\) and \(z=0)\). The wire carries a current of \(7.00 \mathrm{~A}\) in the positive \(x\) -direction. What is the magnitude and the direction of the force on a particle with a charge of 9.00 C located at \((+1.00 \mathrm{~m},+2.00 \mathrm{~m}, 0),\) when it has a velocity of \(3000 . \mathrm{m} / \mathrm{s}\) in each of the following directions? a) the positive \(x\) -direction c) the negative \(z\) -direction b) the positive \(y\) -direction

A wire of radius \(R\) carries current \(i\). The current density is given by \(J=J_{0}(1-r / R),\) where \(r\) is measured from the center of the wire and \(J_{0}\) is a constant. Use Ampere's Law to find the magnetic field inside the wire at a distance \(r

A long solenoid (diameter of \(6.00 \mathrm{~cm}\) ) is wound with 1000 turns per meter of thin wire through which a current of 0.250 A is maintained. A wire carrying a current of 10.0 A is inserted along the axis of the solenoid. What is the magnitude of the magnetic field at a point \(1.00 \mathrm{~cm}\) from the axis?

A long, straight cylindrical tube of inner radius \(a\) and outer radius \(b\), carries a total current \(i\) uniformly across its cross section. Determine the magnitude of the magnetic field from the tube at the midpoint between the inner and outer radii.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free