An 8 -turn coil has square loops measuring \(0.200 \mathrm{~m}\) along a side and a resistance of \(3.00 \Omega\). It is placed in a magnetic field that makes an angle of \(40.0^{\circ}\) with the plane of each loop. The magnitude of this field varies with time according to \(B=1.50 t^{3}\), where \(t\) is measured in seconds and \(B\) in teslas. What is the induced current in the coil at \(t=2.00 \mathrm{~s} ?\)

Short Answer

Expert verified
Question: Calculate the induced current in the coil at time t = 2.00 seconds, given the parameters as mentioned in the solution. Answer: The induced current in the coil at time t = 2.00 s is 3.072 A.

Step by step solution

01

Write down the given information

We are given the following information: 1. Number of turns (n) in the coil: 8 2. Side of the square loop (s): 0.200 m 3. Resistance of the coil (R): 3.00 Ω 4. Angle between magnetic field and plane of the loop (θ): 40.0° 5. Time-dependent magnetic field (B): \(1.50 t^3\), where t is in seconds and B is in teslas 6. Time for which induced current is needed (t): 2.00 s
02

Compute the magnetic flux

To compute the magnetic flux, we first need to find the magnetic field component parallel to the plane of the loop (B_parallel). This can be calculated using the angle θ: B_parallel(t) = B(t) * cos(θ) At t = 2.00 s, we have: B_parallel(2) = \(1.50 \times 2^3\) * cos(40°) = 12.0 T * cos(40°) = 9.218 T Now, we can find the magnetic flux (Φ) through a single loop using the formula: Φ = B_parallel * Area Area of a single loop is s^2, so: Φ = 9.218 T * \((0.200 \mathrm{~m})^2\) = 0.3687 Tm² Since there are 8 loops, Total magnetic flux = 8 * Φ = 2.9548 Tm²
03

Compute the induced emf

Now, we apply Faraday's law of electromagnetic induction to compute the induced EMF (ε), given as: ε = -n * (dΦ/dt) First, we need to differentiate the magnetic flux with respect to time: Φ(t) = n * B_parallel(t) * \((0.200 \mathrm{~m})^2\) Differentiating with respect to t, we get: dΦ/dt = n * dB_parallel/dt * \((0.200 \mathrm{~m})^2\) Now, we find dB_parallel/dt: B_parallel(t) = \(1.50t^3\) * cos(40°) Differentiating with respect to t: dB_parallel/dt = 3 * 1.50t² * cos(40°) = 4.50t² * cos(40°) At t = 2.00 s, we get: dB_parallel/dt(2) = 4.50 * \(2^2\) * cos(40°) = 36.0 T/s Now we can find dΦ/dt: dΦ/dt(2) = 8 * 36.0 T/s * \((0.200 \mathrm{~m})^2\) = 1.152 Tm²/s Finally, we compute the induced emf using Faraday's law: ε = -8 * 1.152 Tm²/s = -9.216 V Note that the negative sign indicates the direction of induced current (Lenz's law).
04

Compute the induced current

We have the induced emf and the coil's resistance, so we can use Ohm's law to compute the induced current (I): I = ε / R So, the induced current at t = 2.00 s: I = |-9.216 V| / 3.00 Ω = 3.072 A The induced current in the coil at time t = 2.00 s is 3.072 A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Understanding magnetic flux is crucial to comprehending how induced currents in coils work. Magnetic flux, denoted by the Greek letter \( \Phi \), refers to the amount of magnetic field that passes through a given area. It's the product of the magnetic field strength, the area it penetrates, and the cosine of the angle between the field direction and the normal to the surface (\( \cos(\theta) \) for flat surfaces). In mathematical terms, \( \Phi = B \times A \times \cos(\theta) \), where \( B \) is the magnetic field, \( A \) is the area, and \( \theta \) is the angle between the field lines and the perpendicular to the surface.

Now, when it comes to a coil with multiple turns, we must consider each loop. The total flux through the coil is essentially the sum of the flux through each turn. Therefore, if you have a coil with \( n \) turns, the total magnetic flux would be \( n \times \Phi \) for each individual loop. This concept directly informs Faraday's law, which relates magnetic flux to induced electromotive force (emf).
Faraday's Law of Electromagnetic Induction
Faraday's law of electromagnetic induction is a cornerstone of electromagnetism, defining how a voltage or emf is induced in a circuit due to changes in magnetic flux. Faraday's law states that the induced emf in any closed circuit is equal to the negative rate of change of the magnetic flux through the circuit. The formula is beautifully simple: \( \epsilon = -n \frac{d\Phi}{dt} \) where \( \epsilon \) is the induced emf, \( n \) is the number of turns of the coil, and \( \frac{d\Phi}{dt} \) represents the rate of change of magnetic flux over time.

When the change in magnetic flux is positive, the negative sign in Faraday's law tells us that the induced current creates a magnetic field opposing the original change, a marvelously self-regulating system consistent with Lenz's law. The usefulness of Faraday's law is immense; it forms the working principle behind many electrical machines and transformers.
Lenz's Law
Lenz's law is a fundamental principle that gives us the direction of the induced current resulting from any change in magnetic flux. Lenz's law states that the direction of any induced current is such that it'll oppose the change in magnetic flux that produced it. This law is essentially a statement of energy conservation and aligns with the negative sign in Faraday's law of electromagnetic induction.

When studying induced currents, Lenz's law is integral to understanding why currents behave as they do. In our coil example, when the magnetic field through the coil increases, the induced current generates a magnetic field that attempts to reduce the increase. Conversely, if the flux decreases, the induced current's magnetic field works to maintain it. Lenz's law helps us predict the effects of electromagnetic induction in various technology, including generators and inductive sensors.
Time-Dependent Magnetic Field
A time-dependent magnetic field is one that changes in magnitude or direction with time. Such variation is essential for electromagnetic induction to occur, according to Faraday's law. Whether the field increases, decreases or rotates with time, any change is capable of inducing a voltage in a neighboring conductor.

For instance, a magnetic field increasing linearly with time — such as the one described by the formula \( B = 1.50t^3 \) — will induce an emf whose magnitude is proportional to the rate of change of the field. The faster the field changes, the greater the induced emf and, consequently, the current in a circuit with a given resistance. Understanding time-dependent fields enables us to engineer devices for converting kinetic energy into electrical energy, like in the case of dynamos and alternators used in power generation.

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Most popular questions from this chapter

A student wearing a 15.0 -g gold band with radius \(0.750 \mathrm{~cm}\) (and with a resistance of \(61.9 \mu \Omega\) and a specific heat capacity of \(c=129 \mathrm{~J} / \mathrm{kg}^{\circ} \mathrm{C}\) ) on her finger moves her finger from a region having a magnetic field of \(0.0800 \mathrm{~T}\), pointing along her finger, to a region with zero magnetic field in \(40.0 \mathrm{~ms}\). As a result of this action, thermal energy is added to the band due to the induced current, which raises the temperature of the band. Calculate the temperature rise in the band, assuming all the energy produced is used in raising the temperature.

A magnetar (magnetic neutron star) has a magnetic field near its surface of magnitude \(4.0 \cdot 10^{10} \mathrm{~T}\) a) Calculate the energy density of this magnetic field. b) The Special Theory of Relativity associates energy with any mass \(m\) at rest according to \(E_{0}=m c^{2}(\) more on this in Chapter 35 ). Find the rest mass density associated with the energy density of part (a).

A circular conducting loop with radius \(a\) and resistance \(R_{2}\) is concentric with a circular conducting loop with radius \(b \gg a(b\) much greater than \(a\) ) and resistance \(R_{1}\). A time-dependent voltage is applied to the larger loop, having a slow sinusoidal variation in time given by \(V(t)=V_{0} \sin \omega t\) where \(V_{0}\) and \(\omega\) are constants with dimensions of voltage and inverse time, respectively. Assuming that the magnetic field throughout the inner loop is uniform (constant in space) and equal to the field at the center of the loop, derive expressions for the potential difference induced in the inner loop and the current \(i\) through that loop.

What is the resistance in an RL circuit with \(L=36.94 \mathrm{mH}\) if the time taken to reach \(75 \%\) of its maximum current value is \(2.56 \mathrm{~ms} ?\)

Large electric fields are certainly a hazard to the human body, as they can produce dangerous currents, but what about large magnetic fields? A man \(1.80 \mathrm{~m}\) tall walks at \(2.00 \mathrm{~m} / \mathrm{s}\) perpendicular to a horizontal magnetic field of \(5.0 \mathrm{~T} ;\) that is, he walks between the pole faces of a very big magnet. (Such a magnet can, for example, be found in the National Superconducting Cyclotron Laboratory at Michigan State University.) Given that his body is full of conducting fluids, estimate the potential difference induced between his head and feet.

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