Having just learned that there is energy associated with magnetic fields, an inventor sets out to tap the energy associated with the Earth's magnetic field. What volume of space near Earth's surface contains \(1 \mathrm{~J}\) of energy, assuming the strength of the magnetic field to be \(5.0 \cdot 10^{-5} \mathrm{~T} ?\)

Short Answer

Expert verified
Answer: The volume near Earth's surface containing 1 Joule of energy due to the Earth's magnetic field is approximately \(1.01 \cdot 10^{11} \mathrm{m^3}\).

Step by step solution

01

Calculate the energy density of the magnetic field

We can calculate the energy density \(u\) of the Earth's magnetic field using the formula: $$u = \frac{1}{2\mu_0} B^2$$ where \(B = 5.0 \cdot 10^{-5} \mathrm{~T}\) and \(\mu_0 = 4\pi \cdot 10^{-7} \mathrm{~T\cdot m/A}\). Let's find \(u\): $$u = \frac{1}{2 (4\pi \cdot 10^{-7})}\left(5.0 \cdot 10^{-5}\right)^2 \mathrm{J/m^3}$$
02

Calculate the volume containing 1 Joule of energy

Now that we have the energy density \(u\), we can use the formula to find the volume \(V\) that contains 1 Joule of energy: $$V = \frac{1}{u} \cdot E$$ where \(E = 1 \mathrm{~J}\). Plugging in the values: $$V = \frac{1}{(9.8696 \cdot 10^{-12})} \cdot 1 \mathrm{~J}$$
03

Calculate the final volume

To find the final volume, we just need to simplify the expression: $$V = \frac{1}{9.8696 \cdot 10^{-12}} \mathrm{m^3}$$ and the result is: $$V \approx 1.01 \cdot 10^{11} \mathrm{m^3}$$ Thus, the volume near Earth's surface that contains 1 Joule of energy from the Earth's magnetic field is approximately \(1.01 \cdot 10^{11} \mathrm{m^3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Density of Magnetic Field
Understanding the concept of energy density is fundamental when studying magnetic fields. The energy density, represented by the symbol \(u\), is the amount of energy stored in a magnetic field per unit volume. Essentially, it tells us how much magnetic energy is packed into a given space.

The formula for calculating the energy density of a magnetic field is \[u = \frac{1}{2\mu_0} B^2\], where \(B\) represents the magnetic field strength and \(\mu_0\) is the permeability of free space, a constant with the value of \(4\pi \cdot 10^{-7} \mathrm{T\cdot m/A}\). In simpler terms, \(u\) increases with the square of the magnetic field strength, indicating that even small increases in field strength can lead to significant rises in energy density.

When examining the Earth's magnetic field, which is relatively weak, the energy density is accordingly low. This means that to harvest a sizable amount of energy, a large volume of space would be needed. This principle underlies the inventor's quest in the exercise to tap into the energy contained within the Earth's magnetic field.
Magnetic Field Strength
Magnetic field strength, denoted by \(B\), measures the magnitude of the magnetic field at a specific location. It is expressed in Teslas (T), a unit that quantifies the level of magnetism experienced by a charged particle moving through that field. The magnetic field strength around Earth varies, but near its surface, it is typically around \(5.0 \cdot 10^{-5} \mathrm{T}\).

Despite being invisible to the naked eye, the Earth's magnetic field has real effects, such as the protection it provides from solar winds and the guidance it offers to compass needles. In the context of the exercise, \(B\) represents a key variable in calculating the energy density and, subsequently, the volume of space that would need to be utilized to extract a certain amount of energy from the magnetic field.
Magnetic Field Energy Calculation
Calculating the energy contained in a magnetic field involves using the energy density and the volume of the space in question. Once the energy density \(u\) is known, we can find the volume \(V\) that contains a specific amount of energy \(E\) with the formula \[V = \frac{E}{u}\]. The steps provided demonstrate this calculation, leading to the determination that a colossal volume of approximately \(1.01 \cdot 10^{11} \mathrm{m^3}\) is required to harvest merely 1 Joule of energy from Earth's magnetic field.

This exercise illustrates a practical scenario where understanding the theoretical concepts of magnetic field energy is essential. Although Earth's magnetic field provides various ecosystem services, harnessing a significant amount of energy from it is impractical due to the vast spaces involved, reasserting the value of exploring diverse sources of renewable energy.

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Most popular questions from this chapter

Large electric fields are certainly a hazard to the human body, as they can produce dangerous currents, but what about large magnetic fields? A man \(1.80 \mathrm{~m}\) tall walks at \(2.00 \mathrm{~m} / \mathrm{s}\) perpendicular to a horizontal magnetic field of \(5.0 \mathrm{~T} ;\) that is, he walks between the pole faces of a very big magnet. (Such a magnet can, for example, be found in the National Superconducting Cyclotron Laboratory at Michigan State University.) Given that his body is full of conducting fluids, estimate the potential difference induced between his head and feet.

A solid metal disk of radius \(R\) is rotating around its center axis at a constant angular speed of \(\omega .\) The disk is in a uniform magnetic field of magnitude \(B\) that is oriented normal to the surface of the disk. Calculate the magnitude of the potential difference between the center of the disk and the outside edge.

Which of the following statements regarding self induction is correct? a) Self-induction occurs only when a direct current is flowing through a circuit. b) Self-induction occurs only when an alternating current is flowing through a circuit. c) Self-induction occurs when either a direct current or an alternating current is flowing through a circuit. d) Self-induction occurs when either a direct current or an alternating current is flowing through a circuit as long as the current is varying.

Two parallel conducting rails with negligible resistance are connected at one end by a resistor of resistance \(R\), as shown in the figure. The rails are placed in a magnetic field \(\vec{B}_{\text {ext }},\) which is perpendicular to the plane of the rails. This magnetic field is uniform and time independent. The distance between the rails is \(\ell\). A conducting rod slides without friction on top of the two rails at constant velocity \(\vec{v}\). a) Using Faraday's Law of Induction, calculate the magnitude of the potential difference induced in the moving rod. b) Calculate the magnitude of the induced current in the \(\operatorname{rod}, i_{\text {ind }}\). c) Show that for the rod to move at a constant velocity as shown, it must be pulled with an external force, \(\vec{F}_{\mathrm{ext}},\) and calculate the magnitude of this force. d) Calculate the work done, \(W_{\text {ext }},\) and the power generated, \(P_{\text {ext }}\), by the external force in moving the rod. e) Calculate the power used (dissipated) by the resistor, \(P_{\mathrm{R}}\). Explain the correlation between this result and those of part (d).

A helicopter hovers above the north magnetic pole in a magnetic field of magnitude 0.426 G perpendicular to the ground. The helicopter rotors are \(10.0 \mathrm{~m}\) long, are made of aluminum, and rotate about the hub with a rotational speed of \(10.0 \cdot 10^{4} \mathrm{rpm} .\) What is the potential difference from the hub of the rotor to the end?

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