Chapter 30: Problem 22
Why can't a transformer be used to step up or step down the voltage in a DC circuit?
Chapter 30: Problem 22
Why can't a transformer be used to step up or step down the voltage in a DC circuit?
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Get started for freeThe phase constant, \(\phi\), between the voltage and the current in an AC circuit depends on the ______. a) inductive reactance b) capacitive reactance c) resistance d) all of the above
A series circuit contains a \(100.0-\Omega\) resistor, a \(0.500-\mathrm{H}\) inductor, a 0.400 - \(\mu\) F capacitor, and a time-varying source of emf providing \(40.0 \mathrm{~V}\). a) What is the resonant angular frequency of the circuit? b) What current will flow through the circuit at the resonant frequency?
A series RLC circuit is in resonance when driven by a sinusoidal voltage at its resonant frequency, \(\omega_{0}=(L C)^{-1 / 2}\) But if the same circuit is driven by a square-wave voltage (which is alternately on and off for equal time intervals), it will exhibit resonance at its resonant frequency and at \(\frac{1}{3}, \frac{1}{5}\), \(\frac{1}{7}, \ldots,\) of this frequency. Explain why.
A variable capacitor used in an RLC circuit produces a resonant frequency of \(5.0 \mathrm{MHz}\) when its capacitance is set to \(15 \mathrm{pF}\). What will the resonant frequency be when the capacitance is increased to \(380 \mathrm{pF} ?\)
The quality factor, \(Q\), of a circuit can be defined by \(Q=\omega_{0}\left(U_{E}+U_{B}\right) / P .\) Express the quality factor of a series RLC circuit in terms of its resistance \(R\), inductance \(L\), and capacitance \(C .\)
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