An AC power source with \(V_{\mathrm{m}}=220 \mathrm{~V}\) and \(f=60.0 \mathrm{~Hz}\) is connected in a series RLC circuit. The resistance, \(R\), inductance, \(L\), and capacitance, \(C\), of this circuit are, respectively, \(50.0 \Omega, 0.200 \mathrm{H},\) and \(0.040 \mathrm{mF}\). Find each of the following quantities: a) the inductive reactance b) the capacitive reactance c) the impedance of the circuit d) the maximum current through the circuit e) the maximum potential difference across each circuit element

Short Answer

Expert verified
Question: In a series RLC circuit connected to an AC power source with maximum voltage 220 V and frequency 60.0 Hz, the resistance is 50.0 Ω, inductance is 0.200 H, and capacitance is 0.040 mF. Calculate the following quantities: a) inductive reactance b) capacitive reactance c) impedance of the circuit d) maximum current through the circuit e) maximum potential difference across each circuit element Answer: a) Inductive reactance, \(X_L = 75.4 \Omega\). b) Capacitive reactance, \(X_C = 66.32 \Omega\). c) Impedance of the circuit, \(Z = 54.8 \Omega\). d) Maximum current through the circuit, \(I_{m} = 4.01 A\). e) Maximum potential difference across each circuit element: \(V_R = 200.5 V\), \(V_L = 302.3 V\), and \(V_C = 266.0 V\).

Step by step solution

01

Calculate inductive reactance \(X_L\)

First, we will find the inductive reactance \(X_L\) using the formula \(X_L=2\pi fL\). Plug in the given values of frequency and inductance to get \(X_L = 2\pi(60.0Hz)(0.200H)\).
02

Calculate capacitive reactance \(X_C\)

Next, we will find the capacitive reactance \(X_C\) using the formula \(X_C=\frac{1}{2\pi fC}\). Plug in the given values of frequency and capacitance to get \(X_C = \frac{1}{2\pi(60.0Hz)(0.040\times10^{-3}F)}\).
03

Calculate impedance of the circuit \(Z\)

Now, we will calculate the impedance \(Z\) using the formula \(Z=\sqrt{R^2+(X_L-X_C)^2}\). Plug in the values of resistances and reactances from Steps 1 and 2 to get \(Z = \sqrt{(50.0\Omega)^2+(X_L-X_C)^2}\).
04

Calculate maximum current \(I_{m}\)

Then, we will find the maximum current \(I_{m}\) through the circuit using the formula \(I_{m}=\frac{V_{m}}{Z}\). Plug in the values of maximum voltage and impedance from Steps 3 to get \(I_{m} = \frac{220V}{Z}\).
05

Calculate maximum potential difference across each circuit element

Finally, we will find the maximum potential difference across each circuit element using the formulas \(V_R=I_{m}R\), \(V_L=I_{m}X_L\), \(V_C=I_{m}X_C\). Plug in the values of maximum current, resistance, and reactances from Steps 1, 2, and 4 to get \(V_R = I_{m}(50.0\Omega)\), \(V_L = I_{m}X_L\), and \(V_C = I_{m}X_C\).

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