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Chapter 33: Problem 3

A converging lens will be used as a magnifying glass. In order for this to work, the object must be placed at a distance a) \(d_{\mathrm{o}}>f\). c) \(d_{\mathrm{o}}

Short Answer

Expert verified
a) \(d_o > f\) b) \(d_o = f\) c) \(d_o < f\) Answer: c) \(d_o < f\)

Step by step solution

01

Conditions for magnification

A lens works as a magnifying glass when it produces a virtual, upright, and magnified image of the object. For a converging lens to produce such an image, the object must be placed within its focal length, meaning that it should be closer to the lens than the focal length. In other words, the object distance \(d_o < f\). Now let's check each of the given options to see which one matches the condition we found.
02

Evaluate option a

Option a suggests that the object should be placed at a distance \(d_o > f\). If the object is placed at a position farther than the focal length, the converging lens will produce a real and inverted image instead of a virtual and upright one. Hence, the lens will not work as a magnifying glass in this case. So, option a is an incorrect choice.
03

Evaluate option b

Option b suggests that the object should be placed at a distance \(d_o = f\), which means the object will be placed exactly at the focal point on the object side. In this case, the converging lens will form an image at infinity, which is not useful for magnification either. Therefore, option b is also an incorrect choice.
04

Evaluate option c

Option c suggests that the object should be placed at a distance \(d_o < f\). As we mentioned in Step 1, placing the object at a distance less than the lens' focal length produces a virtual, upright, and magnified image, which is the desired condition for a magnifying glass. Thus, option c is the correct choice. Hence, the right distance to place the object for a converging lens to work as a magnifying glass is \(d_o < f\), making option (c) the correct answer.

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Most popular questions from this chapter

How large does a \(5.0-\mathrm{mm}\) insect appear when viewed with a system of two identical lenses of focal length \(5.0 \mathrm{~cm}\) separated by a distance \(12 \mathrm{~cm}\) if the insect is \(10.0 \mathrm{~cm}\) from the first lens? Is the image real or virtual? Inverted or upright?

LASIK surgery uses a laser to modify the a) curvature of the retina. b) index of refraction of the aqueous humor. c) curvature of the lens. d) curvature of the cornea.

Where is the image formed if an object is placed \(25 \mathrm{~cm}\) from the eye of a nearsighted person. What kind of a corrective lens should the person wear? a) Behind the retina. Converging lenses. b) Behind the retina. Diverging lenses. c) In front of the retina. Converging lenses. d) In front of the retina. Diverging lenses.

In H.G. Wells's classic story The Invisible Man, a man manages to change the index of refraction of his body to 1.0 ; thus, light would not bend as it enters his body (assuming he is in air and not swimming). If the index of refraction of his eyes were equal to one, would he be able to see? If so, how would things appear?

Two distant stars are separated by an angle of 35 arcseconds. If you have a refracting telescope whose objective lens focal length is \(3.5 \mathrm{~m}\), what focal length eyepiece do you need in order to observe the stars as though they were separated by 35 arcminutes?
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