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Chapter 33: Problem 36

To study a tissue sample better, a pathologist holds a \(5.00-\mathrm{cm}\) focal length magnifying glass \(3.00 \mathrm{~cm}\) from the sample. How much magnification can he get from the lens?

Short Answer

Expert verified
Answer: The magnification provided by the magnifying glass is approximately 0.625 times.

Step by step solution

01

Write down the known values

We are given: Focal length of the magnifying glass (f) = 5.00 cm Distance between the lens and the tissue sample (u) = -3.00 cm (negative because the object is on the left side of the lens) We need to find the magnification (M).
02

Use the lens formula to find the image distance (v)

The lens formula is given by: \(\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\) Plug in the given values of f and u: \(\frac{1}{5.00} = \frac{1}{-3.00} + \frac{1}{v}\) To solve for v, we can first find the common denominator and then solve for v: \(\frac{1}{5.00} + \frac{1}{3.00} = \frac{1}{v}\) \(v = \frac{1}{\frac{1}{5.00} + \frac{1}{3.00}}\)
03

Calculate the image distance (v)

Now, calculate the value of v by finding the sum of the fractions and taking the reciprocal: \(v = \frac{1}{\frac{1}{5.00} + \frac{1}{3.00}} = \frac{1}{\frac{8}{15}}\) \(v = \frac{15}{8}\) \(v \approx 1.875 \mathrm{~cm}\)
04

Use the magnification formula to find the magnification (M)

The magnification formula is given by: \(M = -\frac{v}{u}\) Plug in the values of v and u: \(M = -\frac{1.875}{-3.00}\)
05

Calculate the magnification (M)

Now, calculate the magnification (M): \(M = \frac{1.875}{3.00}\) \(M \approx 0.625\) So, the pathologist can get a magnification of approximately 0.625 times from the lens.

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Most popular questions from this chapter

Several small drops of paint (less than \(1 \mathrm{~mm}\) in diameter) splatter on a painter's eyeglasses, which are approximately \(2 \mathrm{~cm}\) in front of the painter's eyes. Do the dots appear in what the painter sees? How do the dots affect what the painter sees?

The object (upright arrow) in the following system has a height of \(2.5 \mathrm{~cm}\) and is placed \(5.0 \mathrm{~cm}\) away from a converging (convex) lens with a focal length of \(3.0 \mathrm{~cm}\). What is the magnification of the image? Is the image upright or inverted? Confirm your answers by ray tracing.

You are experimenting with a magnifying glass (consisting of a single converging lens) at a table. You discover that by holding the magnifying glass \(92.0 \mathrm{~mm}\) above your desk, you can form a real image of a light that is directly overhead. If the distance between the light and the table is \(2.35 \mathrm{~m},\) what is the focal length of the lens?

Where is the image formed if an object is placed \(25 \mathrm{~cm}\) from the eye of a nearsighted person. What kind of a corrective lens should the person wear? a) Behind the retina. Converging lenses. b) Behind the retina. Diverging lenses. c) In front of the retina. Converging lenses. d) In front of the retina. Diverging lenses.

Galileo discovered the moons of Jupiter in the fall of \(1609 .\) He used a telescope of his own design that had an objective lens with a focal length of \(f_{o}=40.0\) inches and an eyepiece lens with a focal length of \(f_{e}=2.00\) inches. Calculate the magnifying power of Galileo's telescope.
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