Chapter 33: Problem 6
LASIK surgery uses a laser to modify the a) curvature of the retina. b) index of refraction of the aqueous humor. c) curvature of the lens. d) curvature of the cornea.
Chapter 33: Problem 6
LASIK surgery uses a laser to modify the a) curvature of the retina. b) index of refraction of the aqueous humor. c) curvature of the lens. d) curvature of the cornea.
All the tools & learning materials you need for study success - in one app.
Get started for freeAn object is \(6.0 \mathrm{~cm}\) from a converging thin lens along the axis of the lens. If the lens has a focal length of \(9.0 \mathrm{~cm}\), determine the image magnification.
For a microscope to work as intended, the separation between the objective lens and the eyepiece must be such that the intermediate image produced by the objective lens will occur at a distance (as measured from the optical center of the eyepiece) a) slightly larger than the focal length. b) slightly smaller than the focal length. c) equal to the focal length. d) The position of the intermediate image is irrelevant.
Two refracting telescopes are used to look at craters on the Moon. The objective focal length of both telescopes is \(95.0 \mathrm{~cm}\) and the eyepiece focal length of both telescopes is \(3.80 \mathrm{~cm} .\) The telescopes are identical except for the diameter of the lenses. Telescope A has an objective diameter of \(10.0 \mathrm{~cm}\) while the lenses of telescope \(\mathrm{B}\) are scaled up by a factor of two, so that its objective diameter is \(20.0 \mathrm{~cm}\). a) What are the angular magnifications of telescopes \(A\) and \(B\) ? b) Do the images produced by the telescopes have the same brightness? If not, which is brighter and by how much?
As a high-power laser engineer you need to focus a 1.06-mm diameter laser beam to a 10.0 - \(\mu\) m diameter spot \(20.0 \mathrm{~cm}\) behind the lens. What focal length lens would you use?
Some reflecting telescope mirrors utilize a rotating tub of mercury to produce a large parabolic surface. If the tub is rotating on its axis with an angular frequency \(\omega,\) show that the focal length of the resulting mirror is: \(f=g / 2 \omega^{2}\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.