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Chapter 34: Problem 39

What is the largest slit width for which there are no minima when the wavelength of the incident light on the single slit is \(600 . \mathrm{nm} ?\)

Short Answer

Expert verified
Answer: The largest slit width for which there are no minima when the wavelength of the incident light is 600 nm is 600 nm.

Step by step solution

01

Understand the Concept of Single-Slit Diffraction

Single-slit diffraction occurs when light waves pass through a narrow slit and then diffract, or bend, around the edges of the slit. This bending results in a pattern of light and dark areas on a screen behind the slit due to constructive and destructive interference of the light waves.
02

Know the Condition for Destructive Interference

In the single-slit diffraction pattern, destructive interference happens when the path length difference between two waves arriving at the screen is an odd multiple of half the wavelength (λ/2, 3λ/2, 5λ/2, etc). For the first minimum, the path length difference between the waves from the top and bottom edges of the slit should be λ/2.
03

Derive the Slit Width Formula

Let's consider a single slit of width 'a' and let 'θ' be the angle with respect to the central maximum where the first minimum occurs. According to the geometry of the diffraction pattern, the path length difference is (a/2)sin(θ). Now, equating the path length difference to λ/2. (a/2)sin(θ) = λ/2 Now, rearrange the equation to get the formula for the slit width, a. a = λ/sin(θ)
04

Calculate the Largest Slit Width for No Minima

If there are no minima, it means that the angle θ should be larger than 90 degrees for the first minimum, but this is not possible since the maximum value of θ for destructive interference is 90 degrees. So we should analyze the situation for θ = 90 degrees. a = (600 * 10^{-9}m) / sin(90) a = 600 nm The largest slit width for which there are no minima when the wavelength of the incident light is 600 nm is 600 nm.

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Most popular questions from this chapter

Plane light waves are incident on a single slit of width \(2.00 \mathrm{~cm} .\) The second dark fringe is observed at \(43.0^{\circ}\) from the central axis. What is the wavelength of the light?

A Young's interference experiment is performed with monochromatic green light \((\lambda=540 \mathrm{nm}) .\) The separation between the slits is \(0.100 \mathrm{~mm},\) and the interference pattern on a screen shows the first side maximum \(5.40 \mathrm{~mm}\) from the center of the pattern. How far away from the slits is the screen?

An instructor uses light of wavelength \(633 \mathrm{nm}\) to create a diffraction pattern with a slit of width \(0.135 \mathrm{~mm} .\) How far away from the slit must the instructor place the screen in order for the full width of the central maximum to be \(5.00 \mathrm{~cm} ?\)

Many astronomical observatories, and especially radio observatories, are coupling several telescopes together. What are the advantages of this?

A two-slit apparatus is covered with a red \((670 \mathrm{nm})\) filter. When white light is shone on the filter, on the screen beyond the two-slit apparatus, there are nine interference maxima within the 4.50 -cm-wide central diffraction maximum. When a blue \((450 \mathrm{nm})\) filter replaces the red, how many interference maxima will there be in the central diffraction maximum, and how wide will that diffraction maximum be?
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