A double slit is opposite the center of a 1.8 -m wide screen \(2.0 \mathrm{~m}\) from the slits. The slit separation is \(24 \mu \mathrm{m}\) and the width of each slit is \(7.2 \mu \mathrm{m}\). How many fringes are visible on the screen if the slit is illuminated by \(600 .-\mathrm{nm}\) light?

Short Answer

Expert verified
The width of the screen is 1.8 m. Answer: 36 fringes are visible on the screen.

Step by step solution

01

Calculate the angular separation between bright fringes

We can calculate the angular separation between the bright fringes (maxima) using the double-slit interference formula: \(\theta = \arcsin(\frac{m\lambda}{d})\) Where: - \(\theta\) represents the angular separation between adjacent maxima, - \(m\) represents the order of the maxima, - \(\lambda\) represents the wavelength of the light (600 nm), - and \(d\) represents the slit separation (24 µm). Since we are interested in the angle between adjacent maxima, we will use \(m = 1\): \(\theta = \arcsin(\frac{1 \times 600\,\mathrm{nm}}{24\,\mu\mathrm{m}})\) \(\theta \approx 0.025\) radians
02

Calculate the distance between adjacent fringes on the screen

We can now convert the angular separation to a linear distance on the screen using the following formula: \(y = L \times \tan(\theta)\) Where: - \(y\) represents the distance between adjacent fringes, - \(L\) represents the distance between the slits and the screen (2.0 m), - and \(\theta\) represents the angular separation between adjacent maxima. Substitute the values and calculate \(y\): \(y = 2.0\,\mathrm{m} \times \tan(0.025) \approx 0.05\,\mathrm{m}\)
03

Determine the total number of fringes visible on the screen

To calculate the total number of fringes visible on the screen, we will divide the width of the screen (1.8 m) by the distance between adjacent fringes (\(y\)): Total fringes = \(\frac{1.8\,\mathrm{m}}{0.05\,\mathrm{m}} = 36\) There are 36 fringes visible on the screen.

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