Rocket A passes Earth at a speed of \(0.75 c\). At the same time, rocket B passes Earth moving \(0.95 c\) relative to Earth in the same direction. How fast is B moving relative to A when it passes \(A ?\)

Short Answer

Expert verified
Answer: The relative speed of Rocket B with respect to Rocket A is approximately 0.9926c.

Step by step solution

01

1. Understand the relativistic velocity addition formula

The relativistic velocity addition formula is given by: $$ V = \frac{u+v}{1+\frac{uv}{c^2}} $$ where \(V\) is the relative speed of the two objects, \(u\) is one object's speed relative to a reference frame (in this case, Earth), \(v\) is the other object's speed relative to the same reference frame, and \(c\) is the speed of light.
02

2. Substitute the given values into the formula

In our problem, the speed of Rocket A relative to Earth is \(u = 0.75c\), and the speed of Rocket B relative to Earth is \(v = 0.95c\). We'll now substitute these values into the relativistic velocity addition formula: $$ V = \frac{(0.75c) + (0.95c)}{1 + \frac{(0.75c)(0.95c)}{c^2}} $$
03

3. Simplify the expression

We can simplify the expression by factoring out \(c\) in the numerator and canceling out with the \(c^2\) in the denominator: $$ V = \frac{c(0.75 + 0.95)}{1 + \frac{0.75 \cdot 0.95}{1}} $$
04

4. Calculate the relative speed

Now, we can compute the relative speed by solving for V: $$ V = \frac{c(1.7)}{1 + 0.7125} $$ $$ V = \frac{1.7c}{1.7125} $$ $$ V \approx 0.9926c $$ So, Rocket B is moving at a speed of approximately \(0.9926c\) relative to Rocket A when it passes Rocket A.

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