Ultra-high-energy gamma rays are found to come from the Equator of our galaxy, with energies up to \(3.5 \cdot 10^{12} \mathrm{eV}\). What is the wavelength of this light? How does the energy of this light compare to the rest mass of a proton?

Short Answer

Expert verified
Answer: The wavelength of the ultra-high-energy gamma ray is \(3.56 \cdot 10^{-17} \mathrm{m}\). The energy of the gamma ray is 3733 times the rest mass energy of a proton.

Step by step solution

01

Convert the energy to SI units

Given energy, \(E = 3.5 \cdot 10^{12} \mathrm{eV}\). To convert it into SI units (joules), we need to multiply it by the charge of an electron. \(1 \mathrm{eV} = 1.6 \cdot 10^{-19} \mathrm{J}\) So, \(E = 3.5 \cdot 10^{12} \mathrm{eV} \times 1.6 \cdot 10^{-19} \frac{\mathrm{J}}{\mathrm{eV}} = 5.6 \cdot 10^{-7} \mathrm{J}\)
02

Calculate the wavelength of the gamma ray

We will use the energy-wavelength relationship given by Planck's constant (\(h\)) and the speed of light (\(c\)). For a photon, the energy-wavelength relationship is given by \(E = h \cdot c / \lambda\) where \(E\) is the energy, and \(\lambda\) is the wavelength. Rearranging for \(\lambda\), we get \(\lambda = h \cdot c / E\) Using the values for Planck's constant (\(h = 6.63 \cdot 10^{-34} \mathrm{Js}\)) and the speed of light (\(c = 3.0 \cdot 10^{8} \mathrm{m/s}\)), we can compute the wavelength as follows: \(\lambda = \frac{6.63 \cdot 10^{-34} \mathrm{Js} \times 3.0 \cdot 10^{8} \mathrm{m/s}}{5.6 \cdot 10^{-7} \mathrm{J}} = 3.56 \cdot 10^{-17} \mathrm{m}\)
03

Compare the energy with the rest mass of a proton

To compare the energy of this light with the rest mass of a proton, we need to convert the proton mass into energy using the mass-energy equivalence formula. Einstein's mass-energy equivalence formula is given by \(E = m \cdot c^2\) where \(m\) is the rest mass of a proton, which is approximately \(1.67 \cdot 10^{-27} \mathrm{kg}\), and \(c\) is the speed of light, \(3.0 \cdot 10^{8} \mathrm{m/s}\). The energy of the proton is given by \(E_\mathrm{proton} = 1.67 \cdot 10^{-27} \mathrm{kg} \times (3.0 \cdot 10^{8} \mathrm{m/s})^2 = 1.50 \cdot 10^{-10} \mathrm{J}\) Now, we will compare this energy with the energy of the gamma ray by taking their ratio \(\frac{E_{\mathrm{gamma}}}{E_\mathrm{proton}} = \frac{5.6 \cdot 10^{-7} \mathrm{J}}{1.50 \cdot 10^{-10} \mathrm{J}} = 3733\) The energy of the ultra-high-energy gamma ray is 3733 times the rest mass energy of a proton.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free