In baseball, a \(100 .-\mathrm{g}\) ball can travel as fast as \(100 . \mathrm{mph}\). What is the de Broglie wavelength of this ball? The Voyager spacecraft, with a mass of about \(250 . \mathrm{kg}\), is currently travelling at \(125,000 \mathrm{~km} / \mathrm{h}\). What is its de Broglie wavelength?

Short Answer

Expert verified
Answer: The de Broglie wavelength of the baseball is 1.48 * 10^-34 meters, and the de Broglie wavelength of the Voyager spacecraft is 7.62 * 10^-38 meters.

Step by step solution

01

Convert the mass and velocity of the baseball to SI units

The mass of the baseball is given in grams and the velocity in miles per hour. Let's convert them to SI units (kilograms and meters per second). - 100 g = 0.1 kg - 100 mph = 44.7 m/s
02

Calculate the de Broglie wavelength for the baseball

We can use the formula λ = h / (m * v) to find the wavelength, where h = 6.626 * 10^-34 Js (Planck's constant), m = 0.1 kg, and v = 44.7 m/s. λ_baseball = (6.626 * 10^-34) / (0.1 * 44.7) = 1.48 * 10^-34 m Now, let's calculate the wavelength for the Voyager spacecraft.
03

Convert the mass and velocity of the Voyager spacecraft to SI units

The mass of the Voyager is given in kilograms and the velocity in kilometers per hour. Let's convert the velocity to SI units (meters per second). - 125,000 km/h = 34,722.22 m/s
04

Calculate the de Broglie wavelength for the Voyager spacecraft

We can use the same formula λ = h / (m * v) to find the wavelength, where h = 6.626 * 10^-34 Js (Planck's constant), m = 250 kg, and v = 34,722.22 m/s. λ_voyager = (6.626 * 10^-34) / (250 * 34,722.22) = 7.62 * 10^-38 m So, the de Broglie wavelength of the baseball is 1.48 * 10^-34 meters, and the de Broglie wavelength of the Voyager spacecraft is 7.62 * 10^-38 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Mechanics
Quantum mechanics is a fundamental theory in physics which describes nature at the smallest scales of energy levels of atoms and subatomic particles. Traditional physics, known as classical mechanics, could not explain phenomena at the atomic and subatomic level. Quantum mechanics provides a mathematical description of much of the dual particle-like and wave-like behavior and interactions of energy and matter. It underpins a host of modern technologies, such as the laser and semiconductor devices that are vital to modern computers and smartphones.

In quantum mechanics, particles have properties of both particles and waves, and one can only predict the probability of where a particle might be – which is fundamentally different from classical mechanics, where objects can have determined positions and velocities. The equation that connects classical and quantum physics is the de Broglie wavelength formula, which implies that matter can exhibit wave-like behavior under certain conditions.
Planck's Constant
Planck's constant, symbolized as \( h \), is a fundamental constant that is very important in the field of quantum mechanics. Its value is approximately \( 6.626 \times 10^{-34} \) joule-seconds. This constant is crucial in the aspect of quantization of energy and has dimensions of energy multiplied by time, which are units of action.

When Max Planck was studying blackbody radiation, he proposed that energy is quantized, and can be given as an integer multiple of an elementary unit \( E = h u \), where \( u \) is the frequency. This discovery led to the quantum revolution in physics. Planck’s constant makes it possible to describe the particle aspect of light and other quantum particles. It is central to the theory of quantum mechanics, appearing in many fundamental equations, including the one used to find the de Broglie wavelength of a particle, highlighting the wave-particle duality.
Wave-Particle Duality
Wave-particle duality is a fundamental concept of quantum mechanics which states that elementary particles such as electrons and photons exhibit both wave-like and particle-like properties. French physicist Louis de Broglie first introduced wave-particle duality in his PhD thesis in 1924, suggesting that just as light has both wave-like and particle-like properties, matter also should have wave-like properties.

The de Broglie wavelength is the wavelength, \( \lambda \), associated with a particle and is related to its momentum, \( p \), through the Planck constant, \( h \): \[ \lambda = \frac{h}{p} \]. The de Broglie hypothesis was confirmed by electron diffraction experiments. For macroscopic objects, such as a baseball or a spacecraft, the associated de Broglie wavelength is usually extremely small, making their wave-like properties very difficult to detect and practically negligible in the classical perspective.

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Most popular questions from this chapter

Now consider de Broglie waves for a (relativistic) particle of mass \(m\), momentum \(p=m v \gamma\), and total energy \(E=m c^{2} \gamma\), with \(\gamma=\left[1-(v / c)^{2}\right]^{-1 / 2}\). The waves have wavelength \(\lambda=h / p\) and frequency \(f=E / h\) as before, but with the relativistic momentum and energy. a) Calculate the dispersion relation for these waves. b) Calculate the phase and group velocities of these waves. Now which corresponds to the classical velocity of the particle?

A blackbody is an ideal system that a) absorbs \(100 \%\) of the light incident upon it, but cannot emit light of its own. b) emits \(100 \%\) of the light it generates, but cannot absorb radiation of its own. c) either absorbs \(100 \%\) of the light incident upon it, or emits \(100 \%\) of the radiation it generates. d) absorbs \(50 \%\) of the light incident upon it, and emits \(50 \%\) of the radiation it generates. e) blackens completely any body that comes in contact with it

Ultra-high-energy gamma rays are found to come from the Equator of our galaxy, with energies up to \(3.5 \cdot 10^{12} \mathrm{eV}\). What is the wavelength of this light? How does the energy of this light compare to the rest mass of a proton?

The existence of a cutoff frequency in the photoelectric effect a) cannot be explained using classical physics. b) shows that the model provided by classical physics is not correct in this case. c) shows that a photon model of light should be used in this case. d) shows that the energy of the photon is proportional to its frequency. e) All of the above.

X-rays having energy of 400.0 keV undergo Compton scattering from a target. The scattered rays are detected at \(25.0^{\circ}\) relative to the incident rays. Find a) the kinetic energy of the scattered \(\mathrm{X}\) -ray, and b) the kinetic energy of the recoiling electron.

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