Which model of the hydrogen atom-the Bohr model or the quantum mechanical model-predicts that the electron spends more time near the nucleus?

Short Answer

Expert verified
Answer: The quantum mechanical model predicts that the electron spends more time near the nucleus due to its probability distribution nature, which places the highest probability densities closer to the nucleus.

Step by step solution

01

Introduce the Bohr model

The Bohr model is an early model of the hydrogen atom, proposed by Niels Bohr in 1913. In this model, the electron orbits the nucleus in discrete circular orbits, similar to planets orbiting around the sun. The electron can only occupy specific energy levels, and it must stay in these fixed orbits unless it gains or loses energy to jump to another orbit.
02

Introduce the quantum mechanical model

The quantum mechanical model, developed in the 1920s, is a more accurate and advanced description of the hydrogen atom. In this model, electrons do not have fixed orbits; instead, their position is described by probability distributions, represented by wave functions. The wave functions, also known as orbitals, represent the areas where the electron is most likely to be found, with no definite path or position around the nucleus.
03

Compare electron distribution in both models

In the Bohr model, the electron spends an equal amount of time in each part of its orbit, meaning that the electron is on average the same distance from the nucleus at all points along the orbit. In quantum mechanical model, however, the probability distribution of the electron's position varies around the nucleus, with the highest probability densities typically found closer to the nucleus. For example, in the ground state of the hydrogen atom (1s orbital), the highest probability density is located at the nucleus itself.
04

Determine which model predicts that the electron spends more time near the nucleus

Based on our comparison of the Bohr model and the quantum mechanical model, it is clear that the quantum mechanical model predicts that the electron spends more time near the nucleus. This is due to its probability distribution nature, which places the highest probability densities closer to the nucleus, unlike the fixed orbits in the Bohr model.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An excited hydrogen atom emits a photon with an energy of \(1.133 \mathrm{eV}\). What were the initial and final states of the hydrogen atom before and after emitting the photon?

Calculate the energy needed to change a single ionized helium atom into a double ionized helium atom (that is, change it from \(\mathrm{He}^{+}\) into \(\mathrm{He}^{2+}\) ). Compare it to the energy needed to ionize the hydrogen atom. Assume that both atoms are in their fundamental state.

Find the energy difference between the ground state of hydrogen and deuterium (hydrogen with an extra neutron in the nucleus)

The muon has the same charge as an electron but a mass that is 207 times greater. The negatively charged muon can bind to a proton to form a new type of hydrogen atom. How does the binding energy \(E_{\mathrm{B} \mu}\) of the muon in the ground state of a muonic hydrogen atom compare with the binding energy \(E_{\mathrm{Be}}\) of an electron in the ground state of a conventional hydrogen atom? a) \(\left|E_{\mathrm{B} \mu}\right| \approx\left|E_{\mathrm{Be}}\right|\) d) \(\left|E_{\mathrm{B} \mu}\right| \approx 200 \mid E_{\mathrm{Be}}\) b) \(\left|E_{\mathrm{B} \mu}\right| \approx 100\left|E_{\mathrm{Be}}\right|\) e) \(\left|E_{\mathrm{B} \mu}\right| \approx\left|E_{\mathrm{Be}}\right| / 200\) c) \(\left|E_{\mathrm{B} \mu}\right| \approx\left|E_{\mathrm{Be}}\right| / 100\)

You hold in your hands both a green \(543-n m, 5.00-m W\) laser and a red, \(633-\mathrm{nm}, 4.00\) -mW laser. Which one will produce more photons per second, and why?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free