An electron in a hydrogen atom is in the \(2 s\) state. Calculate the
probability of finding the electron within a Bohr radius \(\left(a_{0}=0.05295
\mathrm{nm}\right)\) of the proton. The ground-state wave function for hydrogen
is:
$$
\psi_{2 s}(r)=\frac{1}{4 \sqrt{2 \pi a_{0}^{3}}}\left(2-\frac{r}{a_{0}}\right)
e^{-r / 2 a_{0}}.
$$
The integral is a bit tedious, so you may want consider using mathematical
programs such as Mathcad, Mathematica, etc., or doing the integral online at
http://integrals.wolfram.com/index.jsp.